Python 3.3+ : How to suppress exceptions in subprocess. Popen()？

Question

我有一个类，其中包含一些函数，这些函数基本上对数据进行输出检查，此类的函数是使用子进程调用的。现在，如果输出检查失败，子进程将进行 sys.exit 调用，并根据失败的检查使用不同的代码。

在主代码中我有这个:

try:
    exitCode = 0
    #import module for current test
    teststr = os.path.splitext(test)[0]
    os.chdir(fs.scriptFolder)
    test = __import__(teststr)
    #delete old output folder and create a new one
    if  os.path.isdir(fs.outputFolder):
        rmtree(fs.outputFolder)
    os.mkdir(fs.outputFolder)
    # run the test passed into the function as a new subprocess
    os.chdir(fs.pythonFolder)
    myEnv=os.environ.copy()
    myEnv["x"] = "ON"
    testSubprocess = Popen(['python', test.testInfo.network + '.py', teststr], env=myEnv)
    testSubprocess.wait()
    result = addFields(test)
    # poke the data into the postgresql database if the network ran successfully 
    if testSubprocess.returncode == 0:
        uploadToPerfDatabase(result)     
    elif testSubprocess.returncode == 1:
        raise Exception("Incorrect total number of rows on output, expected: " + str(test.testInfo.outputValidationProps['TotalRowCount']))
        exitCode = 1
    elif testSubprocess.returncode == 2:
        raise Exception("Incorrect number of columns on output, expected: " + str(test.testInfo.outputValidationProps['ColumnCount']))
        exitCode = 1
except Exception as e:
    log.out(teststr + " failed", True)
    log.out(str(e))
    log.out(traceback.format_exc())
    exitCode = 1 
return exitCode

现在的输出显示了子进程中 sys.exit 调用的所有回溯和 python 异常。我实际上记录了所有错误，所以我不希望在命令提示符中显示任何内容，除非我手动打印它。我不太确定该怎么做。

Answer 1

您可以使用 subprocess.DEVNULL 标志指定 stderr 写入 os.devnull:

p = Popen(['python', '-c', 'print(1/0)'], stderr=subprocess.DEVNULL)

subprocess.DEVNULL Special value that can be used as the stdin, stdout or stderr argument to Popen and indicates that the special file os.devnull will be used.

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