python - Python列表中的索引包含多个元素。如何访问每个并将它们传递给不同的函数？

Question

我用 Python 3 编写了一段代码，使用 pandas 从表(.csv)中提取值并将它们附加到列表中。我的代码是:

import os
import numpy as np
import csv
import pandas as pd
from generate_xml import write_xml

# global constants
img = None
tl_list = []
br_list = []
object_list = []
tl_x = []
tl_y = []
br_x =[]
br_y =[]


# constants
obj = 'red_hat'

df = pd.read_csv('ring_1_05_sam.csv')
tl_x = df.iloc[5:10, 0:1] - 30
tl_y = df.iloc[5:10, 1:2] - 30
br_x = df.iloc[5:10, 0:1] + 30
br_y = df.iloc[5:10, 1:2] + 30
tl_x = (tl_x.to_string(index=False, header=False))
tl_y = (tl_y.to_string(index=False, header=False))
br_x = (br_x.to_string(index=False, header=False))
br_y = (br_y.to_string(index=False, header=False))
tl_list = (tl_x, tl_y)
br_list = (br_x, br_y)
object_list.append(obj)

print(tl_list[0])

这给了我一个输出

1507.50
1507.44
1507.09
1507.00

如您所见，我的 tl_list[] 处的索引[0] 有这 4 个元素。我的问题是如何单独访问它们？更具体地说，我想将每个值传递给一个函数，一次一个

import os
import numpy as np
import csv
import pandas as pd
from generate_xml import write_xml

# global constants
img = None
tl_list = []
br_list = []
object_list = []
tl_x = []
tl_y = []
br_x =[]
br_y =[]


# constants
obj = 'red_hat'

df = pd.read_csv('ring_1_05_sam.csv')
tl_x = df.iloc[5:10, 0:1] - 30
tl_y = df.iloc[5:10, 1:2] - 30
br_x = df.iloc[5:10, 0:1] + 30
br_y = df.iloc[5:10, 1:2] + 30
tl_x = (tl_x.to_string(index=False, header=False))
tl_y = (tl_y.to_string(index=False, header=False))
br_x = (br_x.to_string(index=False, header=False))
br_y = (br_y.to_string(index=False, header=False))
tl_list = (tl_x, tl_y)
br_list = (br_x, br_y)
object_list.append(obj)

write_xml(image_folder, img, object_list, tl_list, br_list, savedir)
tl_list = []
br_list = []
object_list = []
img = None

这样我的 write_xml 函数将获取 tl_list 和 br_list 中的第一个值，然后依次获取下一个值。现在它同时讲述了所有的值(value)观。我有什么想法可以做到吗？

Answer 1

您可以分割字符串并迭代结果列表:

for tl in tl_list[0].split():
    write_xml(image_folder, img, object_list, tl, br_list, savedir)