python - 当玩家在 5x5 网格上画出 2x2 网格时，如何让游戏停止

Question

基本上我已经有了这个游戏，这些是规则:

-2名玩家；

-玩家 1 从 5x5 网格(矩阵)中选择一个数字，将 0 替换为 1，然后玩家 2 也做同样的事情(他们轮流这样做)；

我的问题是，当玩家用他们的数字制作 2x2 网格(示例)或每个数字 0 已被 1 或 2 替换(这使其成为平局)时，如何使其停止:

            0 0 0 0 0
            0 1 1 2 0
            0 1 1 0 0
            0 0 0 2 0
            0 0 0 0 2

玩家 1 获胜

<小时/>

我的代码:

grid= [[0 for row in range (5)] for col in range (5)]

for i in range (0,10): (THIS IS THE PART THAT I NEED TO REPLACE)

player1_row = int (input ("Player 1, please enter the number of the row (0-4): "))
player1_col = int (input ("Player 1, please enter the number of the column (0-4): "))

grid [player1_row][player1_col]= 1

for s in grid:

    print(*s)

player2_row = int (input ("Player 2, please enter the number of the row (0-4): "))

player2_col = int (input ("Player 2, please enter the number of the column (0-4): "))

grid [player2_row][player2_col]= 2

for s in grid:

    print(*s)

<小时/>

这是我到目前为止的代码:

            def check_for_win(grid):
                for x in range(4):
                    for y in range(4):
                        rect = (grid[x][y], grid[x+1][y], grid[x][y+1], grid[x+1][y+1])
                        if 0 not in rect and 1 not in rect:
                            # player 2 won
                            return 2
                        if 0 not in rect and 2 not in rect:
                            # player 1 won
                            return 1
                return None

            def check_finished(grid):
                for row in grid:
                    if 0 in row:
                        return False
                return True

            grid= [[0 for row in range (5)] for col in range (5)]
            for i in range (0,50):
                player1_row = int (input ("Player 1, please enter the number of the row (0-4): "))
                player1_col = int (input ("Player 1, please enter the number of the column (0-4): "))
                grid [player1_row][player1_col]= 1
                for s in grid:
                    print(*s)
                player2_row = int (input ("Player 2, please enter the number of the row (0-4): "))
                player2_col = int (input ("Player 2, please enter the number of the column (0-4): "))
                grid [player2_row][player2_col]= 2
                for s in grid:
                    print(*s)

                check_for_win(grid)
                check_finished(grid)

这是输出:(它应该停止并说玩家一赢了)

            Player 1, please enter the number of the row (0-4): 1
            Player 1, please enter the number of the column (0-4): 1
            1 1 0 0 0
            1 1 0 0 0
            0 0 2 0 0
            0 0 0 0 2
            0 0 0 0 2
            Player 2, please enter the number of the row (0-4): 

我应该做什么？

Answer 1

您可以编写一个函数来检查其中一名玩家是否获胜，如下所示:

def check_for_win(grid):
    for x in range(4):
        for y in range(4):
            rect = (grid[x][y], grid[x+1][y], grid[x][y+1], grid[x+1][y+1])
            if 0 not in rect and 1 not in rect:
                # player 2 won
                return 2
            if 0 not in rect and 2 not in rect:
                # player 1 won
                return 1
    return None

如果玩家 1 获胜，此函数返回 1；如果玩家 2 获胜，则返回 2；否则返回 None。

检查游戏是否完成非常简单:

def check_finished(grid):
    for row in grid:
        if 0 in row:
            return False
    return True

这能回答你的问题吗？