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python - 使我的代码具有更好的可读性和性能

转载 作者:行者123 更新时间:2023-12-01 08:31:45 24 4
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我有一个 python django 代码,我想让它在阅读和性能方面更好,因为我想将它添加到我的副项目中,而且我是 python 和 django 的新手。有人可以帮我吗

from django.views import View
from django.http import HttpResponse
from django.contrib.gis.geoip2 import GeoIP2
from .models import Victims, Url

g = GeoIP2()

def Get_Ip(request):

x_forwarded_for = request.META.get('HTTP_X_FORWARDED_FOR')
if x_forwarded_for:
ip = x_forwarded_for.split(',')[-1].strip()
else:
ip = request.META.get('REMOTE_ADDR')

return ip

def Get_Country(request):
ip = Get_Ip(request)
country = g.country('31.13.75.36')

return country

def Get_Browser(request):
browser = request.META['HTTP_USER_AGENT']

return browser

def save_vistor_data(request, slug):
ip = Get_Ip(request)
country = Get_Country(request)
browser = Get_Browser(request)

_url = Url()
url = Url.objects.get(slug=slug)

victim = Victims(_url=url, ip_address=ip, country=country, browser=browser)
victim.save()

return HttpResponse('Done')

最佳答案

g = GeoIP2()
IP = '31.13.75.36'

def get_Ip(request):
"""Get IP.

Notes:
This function retrieves/gets IP's.

Args:
request:

Returns:
some object.

Raises:
ConnectionError.


"""
x_forwarded_for = request.META.get('HTTP_X_FORWARDED_FOR')
try:
ip = x_forwarded_for.split(',')[-1].strip()
except Exception:
ip = request.META.get('REMOTE_ADDR')
return ip


def get_country(request):
"""Get country.

"""

ip = Get_Ip(request)
country = g.country(IP)
return country

def get_browser(request):
"""Get Browser

Notes:
What should we know about this function.
That is not already obvious.

Args:
request (type)

Raises:

Returns:

"""
browser = request.META['HTTP_USER_AGENT']
return browser

def save_vistor_data(request, slug):
"""Save visitor data to ...

Notes:
Where is the visitor data going?


Args:
request ():
slug ():

Returns:

"""
ip = Get_Ip(request)
country = Get_Country(request)
browser = Get_Browser(request)

_url = Url()
url = Url.objects.get(slug=slug)

victim = Victims(
_url=url,
ip_address=ip,
country=country,
browser=browser
)

victim.save()

return HttpResponse('Done')

关于python - 使我的代码具有更好的可读性和性能,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/53889964/

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