java - 我的用于输入姓名、年龄以及查看一个人是否年龄足以做某事的 Java 代码有什么问题？

Question

我的代码有什么问题吗？ “if”语句似乎不起作用!我运行该程序并输入我的姓名和年龄。我输入了符合使用该计划的年龄，但它说我太年轻了。我编写了这个，但它不让我使用它!

import java.util.Scanner;

public class learning {
    public static void main(String args[]){

        Scanner uI = new Scanner(System.in);

        System.out.println("Enter your name: ");
        System.out.print(uI.nextLine());
        System.out.println(", enter your age: ");
        uI.nextInt();
        int person = 10;

        if (person > 10){
            System.out.println("You may use this program!");
        }else{
            System.out.println("You may not use this program. You are too young!");
        }

        uI.close();
    }
}

Answer 1

您没有将 uI.nextInt(); 分配给任何 int 变量。喜欢:

    System.out.println(", enter your age: ");
    int personAge = uI.nextInt();
    int person = 10; // instead use this as constant, public static final int MIN_ALLOWED_AGE = 11;

    if (personAge > person){   // if (personAge >= MIN_ALLOWED_AGE){
        System.out.println("You may use this program!");
    }else{
        System.out.println("You may not use this program. You are too young!");
    }