java - 如何在Java中创建临时文件时删除ip和其他数值

Question

我得到的文件名类似于下面的name。我想删除最终的 ip 和另一个数值以获得最终的真实文件名。有没有比使用正则表达式更好的方法来实现这一目标？也许还有其他技术？请帮助我了解这一点。

        String name = "pdf_of_filename_127.10.10.0_8726347.xls";

        System.out.println("Initial File Name :"+name);

        String [] t = name.split("_");
        String finalpart = t[t.length - 1];
        String extension = finalpart.substring(finalpart.lastIndexOf("."),finalpart.length());

        String finalName = "";

        for(int i = 0;i < t.length - 2;i++)
            finalName += t[i]+"_";
        finalName = finalName.substring(0,finalName.length() - 1);

        System.out.println("Final File Name :"+finalName+extension);

输出:

Initial File Name :pdf_of_filename_127.10.10.0_8726347.xls

Final File Name :pdf_of_filename.xls

更多理解:

String name = "pdf_of_filename_53613785621.183761237_127.10.10.0_8726347.xls";

output Expected:
Final File Name :pdf_of_filename_53613785621.183761237.xls

Answer 1

这会起作用:

String name = "pdf_of_filename_53613785621.183761237_127.10.10.0_8726347.xls";
String finalName = name.replaceAll("_(\\d+\\.){3}[\\d_]+","");
System.out.println("finalName = " + finalName);

它删除一个看起来像这样的子字符串:

_             an underscore
(\\d+\\.){3}  followed by 3 times a digit and a period (127.10.10.)
[\\d_]+       then some digits and underscores (0_876347)