python - 如何在Python中检查数组的所有元素是否已填充

Question

我正在使用数组或列表在 Python 中制作一个待办事项列表应用程序。我想检查包含所有“待办任务”的数组是否已满。如果已满，我会通知用户列表已满。 我还是个初学者。

todo_list = ["1.)", "2.)", "3.)", "4.)", "5.)", "6.)", "7.)", "8.)", "9.)", "10.)"]
def addTask(taskName):

  '''
  this is a global variable to keep track of what index the last task was 
  placed in.
  '''


  global x
  x = int(x)
  num = x + 1
  num = int(num)
  taskName = str(taskName)

  '''
  This is what I tried to make the program start from the beginning if the 
  list was full.
  '''

  if x > list_length:
    x = 0
    todo_list[0] = None


  todo_list[x] = str(num) + ".) " + taskName
  x = x+1

  print("Done!")
  main()

Answer 1

您是说您已将可能的任务数量限制为 10 个吗？如果每个列表都附加了一项任务，那么列表应该通知用户它已满？

如果是这样，您就知道空任务是“10.)”，因此它的最大长度为 4(4 个字符)，因此如果任何项目长度小于或等于 4，则它是空的

for task in todo_list:
    if len(task) > 4:
        print('Todo list is full')
        break
    else:
        print('Todo list is full')

我还可以建议更好的方法来创建待办事项列表吗？使用字典。

todo_list = {'clean cat':'incomplete', 'buy milk':'complete'}

添加新任务非常简单!

todo_list['learn python'] = 'incomplete'

并且更新任务更加容易!

todo_list['clean cat'] = 'complete'

这是我的做法:

todo_list = {}

if len(todo_list) == 10:
    print('Sorry, list is full!')
else:
    task_name = input('Task name: ')
    todo_list[task_name] = 'incomplete'

print(todo_list)