python - 如何解决 while 循环不采用 0 或小于它的值的情况？

Question

我无法在 while 循环中计算 0 或更少的哨兵值所需的纵向总长度 = 6 m所需宽度总长度 = 5 m

程序能够满足长度和面包等于0的条件存在循环，但不能满足小于0的负数

我无法计算总长度并将其设为整数。

length = float    
width = float    
sentinal = 0    
d1 = 1

d2 = 1
for i in range(20):

    while d1 != sentinal and d2 != sentinal:

        d1 = float(input("enter room dimension1 (m):"))

        d2 = float(input("enter room dimension2 (m):"))

        if d1 > d2:

                length = d1

                width = d2

                print("length = %.3f m" %(length))

                print("width = %.3f m" %(width))

        elif d2 > d1:

                length = d2

                width = d1

                print("length = %.3f m" %(length))

                print("width = %.3f m"%(width))

Answer 1

请注意:如果这是作业请不要在没有理解所有内容的情况下盲目复制代码，我会尽力通过#注释来解释代码

import math  # required to use ceil() function , ex: ceil(3.2) = 4

def required_length(a, b):  # functions make your code organized
    length = max(a,b)
    width = min(a,b)
    print('length = ', length)
    print('width = ', width)
    print('Total length required lengthways = ', math.ceil(length))
    print('Total length required widthways = ', math.ceil(width))
    print()  # to look nice  print empty line for getting new input


while True:  # loop forever
    a = float(input('enter room dimension 1 (m): '))
    b = float(input('enter room dimension 2 (m): '))

    if a <= 0 or b <= 0:  # exit loop if user entered zero or minus
        print('invalid dimensions')
        break

    required_length(a, b)  # call our function