python - 无法打印代码的第一个和最后一个字符

Question

嘿伙计们，我的程序在一定程度上运行了。我的程序应该检查用户输入中是否有 "A" ，如果完成，它将将该 "A" 与下一个字母交换。

以下是示例:

"tan" = "TNA"
"abracadabra" = "BARCADABARA"
"whoa" = "WHOA"
"aardvark" = "ARADVRAK"
"eggs" = "EGGS"
"a" = "A"

就我而言，这是有效和无效的:

作品:

tan to TNA

不起作用:

abracadabra = BARCADABAR
whoa = WHO
aardvark = ARADVRA
eggs = EGG

a =

a 不等于任何内容。

我的意思是最后一个字符没有打印，我不知道该怎么做。

def scrambleWord(userInput):
    count = 0
    Word_ = ""
    firstLetter_ = ""
    secondLetter_ = ""
    while count < len(userInput):
        if count+1 >=len(userInput):
            break #copy last character
        firstLetter_ = userInput[count] #assigning first letter
        secondLetter_ = userInput[count+1] #assigning next letter
        if firstLetter_ == 'A' and secondLetter_ != 'A':
            Word_ += (secondLetter_ + firstLetter_) #Swap then add both letters
            count+=1
        else:
            Word_+=firstLetter_
        count+=1
    return Word_


def main():
    userInput = input("Enter a word: ")
    finish = scrambleWord(userInput.upper())
    print(finish)

main()

Answer 1

可能是因为您只是在没有将 userinput[count] 写入单词中的情况下进行中断。

if count+1 >=len(userInput):
            Word_ += userInput[count]
            break #copy last character

这应该有帮助