Objective-C 提取 rangeOfString : 返回的范围的索引

Question

如何从

中提取 NSUInteger 索引

NSRange range = [string rangeOfString: substring]

所以我可以在[array objectAtIndex:index]中写这个索引？

Answer 1

// make sure that the substring was actually found:
NSRange result = [string rangeOfString:substring];

if (result.location != NSNotFound)
{
    // make sure that the index exists in the array
    if (result.location < [array count])
    {
        id someObj = [array objectAtIndex:result.location];
        // do something cool with someObj here
    }
}