java - 无论输入是什么，操作的输出始终为零

Question

我有这段代码，变量 s 的输出始终为零:

double v = high; double s; double h;
if (v == 0) {
    s = 0;
    h = 0;
    System.out.println("v and s and h is zeroo" + v + s + h);
} else {
    s = (high - low) / high;
    System.out.println("s is equal to" + s);
    System.out.println("high is equal to" + high);
    System.out.println("low is equal to" + low);
    if (s == 0) {
        h = 0;
        System.out.println("high and low are equals" + high + "==" + low);
    } else {
        double alpha;
        alpha = 60 * (mid - low) / (high - low);
        System.out.println("alpha is : " + alpha);

    }
}

输出示例:

s is equal to0.0
high is equal to139
low is equal to30
high and low are equals139==30

Answer 1

由于 high 和 low 都是 int 类型，因此 s = (high-low)/行中的除法high 使用整数除法，并且由于 high - low 始终小于 high(除非 low 是负数)，因此结果始终为零。

要解决此问题，请将其中一个转换为 double:

s = (high-low)/(double)high;