python - 如何读取从 os.listdir 获取的文件内容？

Question

这个问题已经有答案了:

Python raising FileNotFoundError for file name returned by os.listdir (3 个回答)

已关闭 4 年前。

我正在尝试读取 CSV 文件。我在两个文件夹下有两个 CSV。我收到了 CSV 文件，但当我尝试读取内容时，它说我没有这样的文件或目录。

import os
import csv

def scanCSVFile(folder, output_file_name):
    myfile = open(output_file_name, "a")
    files = os.listdir(folder)
    for file in files:
        if file.endswith('.csv'): #gives two csv files
            with open(file) as csvfile: 
                csvreader = csv.reader(csvfile)
                next(csvreader)
                for line in csvreader:
                    print (line)

    myfile.close()


def openCSV(path):
    scanCSVFile("./src/goi","goi.yml")
    scanCSVFile("./src/kanji","kanji.yml")

openCSV('.')

错误:

C:\Users\Peace\Documents\LMS>python csvToYaml.py 
Traceback (most recent call last): 
File "csvToYaml.py", line 26, in <module> openCSV('.') 
File "csvToYaml.py", line 24, in openCSV scanCSVFile("./src/goi","goi.yml") 
File "csvToYaml.py", line 14, in scanCSVFile with open(file) as csvfile:  
FileNotFoundError: [Errno 2] No such file or directory: 'Pro.csv'

Answer 1

您必须从代码中删除中断

import os,glob

folder_path = r'path'

for filename in glob.glob(os.path.join(folder_path, '*.csv')):
    with open(filename, 'r') as f:
        for line in f:
            print(line)