c# - MVC4 和 jquery : Redirecting to another view using button and also sending parameter object (to another view)

Question

首先，我必须说我是 MVC4 的新手，并且同时学习和开发这个应用程序。在此应用程序中有“index.cshtml” View ，它包含“fresh”span(按钮)。 单击此按钮后，我想要:

1. 重定向到另一个名为“Interview”的 View ，
2. 还想将参数“data”发送到 View ( Controller 操作方法)

Index.cshtml查看代码片段:

.
.
some code
<span class="action-class" id="fresh">Start Fresh Interview</span>
.
.
some code
.
.
$("#fresh").click(function (e) {
            var tech;
            var guid = '@Model.currentInterviewDetails.GuId';
             $.ajax(
            {
                type: "post",
                url: '@Url.Action("Interview","Home")',

                data: {
                    GuId: guid,
                    IntervieweeName: $("#IntervieweName").val(),
                    LevelId: $("#SelectedLevelId").val(),
                    DId: $("#SelectedDesignationId").val(),
                    TrackId: $("#SelectedTrackId").val(),
                    TechId: tech
                },

                success: function (data) {

                }
            });
         });

但是新 View (即 Interview.cshtml)未加载，我可以看到旧 View (index.cshtml)

Interview.cshtml 代码片段:

@model InterviewAssistant.Models.CommonWrapper
@{
    ViewBag.Title = "Interview";
}
@
@if (Model.tech != null && Model.tech.Count() > 0)
{
@Html.HiddenFor(m => m.SelectedTrackId)
     @Html.DropDownListFor(
            m => m.SelectedTechId,
            new SelectList(Model.tech, "TechId", "TechName"),
            string.Empty
            )
}

以下是 Controller 代码:

public ActionResult Interview(InterviewDetailsModel interview)
        {

            string name = System.Web.HttpContext.Current.User.Identity.Name;

            CommonWrapper wrapper = new CommonWrapper();
            wrapper.track = CommonWrapper.GetTracks();
            wrapper.level = CommonWrapper.GetLevel();
            wrapper.designation = CommonWrapper.GetDesignation();
            wrapper.currentInterviewDetails = interview;

            wrapper.tech = (from s in CommonWrapper.GetTechnology()
                            where s.TrackId == interview.TrackId
                            orderby s.TechName
                            select s).ToList();


            return View("Interview", wrapper);

        }

有人可以帮我解决这个问题吗？

提前致谢:-)

Answer 1

以简单的方式，您可以制作 Controller

 public class DefaultController : Controller
{
   Public ActionResult Index()
   {
      Model model = new Model();
      model.TechId = "TechId here";
      model.TechName = "TechName";

      return View(model);
   }

    public ActionResult InterView()
     {
         return View();
     }

    [HttpPost]
    public ActionResult InterView(Model model)
    {
       //retrive model here 

       //return your interview view here
       return View("InterView");
    }
}

在 Index.cshtml 中查看:

@model namespace.model.modelname 

@using (Html.BeginForm("InterView", "Default", FormMethod.Post))
{
    <input type="submit" name="SubmitInterview" value="Submit" />
}