python - 我能弄清楚为什么，但相似度(lk)超出了应有的范围，有人能帮我解决这个问题吗？

Question

相似度(lk)是密码和用户名中相同字母的数量。但是相似度最终比实际单词大。例如，如果密码是“pie”，而猜测是“die”而不是相似度为 2，因为“i”和“E”的数字相同，所以会得出像 18 这样的数字，这个数字太大了。

    import time
    import random
    gus=4
    words_file =open('words.txt','r')
    all_words = words_file.read()
    words_file.close()

    all_words = all_words.split('\n')
    password = 0

    word = random.choice(all_words)
    word2 = random.choice(all_words)
    word3 = random.choice(all_words)
    word4 = random.choice(all_words)
    word5 = random.choice(all_words)
    word6 = random.choice(all_words)
    word7 = random.choice(all_words)

    print("ADMIN OVER PASS ERROR 1231394/123\198")
    a1 = random.randint(1,7)
    if a1==1:
    password=word

if a1==2:
    password=word2

if a1==3:
    password=word3

if a1==4:
    password=word4

if a1==5:
    password=word5
if a1==6:
    password=word6
if a1==7:
    password=word7




print(word)
print(word2)
print(word3)
print(word4)
print(word5)
print(word6)
print(word7)
guss=20

while guss>0:
    print("")
    print("number of tries",guss)
    userans=input("password")
    lk=0
    if userans==password:
        guss=-1
        print("password correct")
    else:
        guss -= 1
        a=userans.count(a)
        b=userans.count(b)
        c=userans.count(c)
        d=userans.count(d)
        e=userans.count(e)
        f=userans.count(f)
        g=userans.count(g)
        h=userans.count(h)
        i=userans.count(i)
        j=userans.count(j)
        k=userans.count(k)
        l=userans.count(l)
        m=userans.count(m)
        n=userans.count(n)
        o=userans.count(o)
        p=userans.count(p)
        q=userans.count(q)
        r=userans.count(r)
        s=userans.count(s)
        t=userans.count(t)
        u=userans.count(u)
        v=userans.count(v)
        w=userans.count(w)
        x=userans.count(x)
        y=userans.count(y)
        z=userans.count(z)

        a2=password.count(a)
        b2=password.count(b)
        c2=password.count(c)
        d2=password.count(d)
        e2=password.count(e)
        f2=password.count(f)
        g2=password.count(g)
        h2=password.count(h)
        i2=password.count(i)
        j2=password.count(j)
        k2=password.count(k)
        l2=password.count(l)
        m2=password.count(m)
        n2=password.count(n)
        o2=password.count(o)
        p2=password.count(p)
        q2=password.count(q)
        r2=password.count(r)
        s2=password.count(s)
        t2=password.count(t)
        u2=password.count(u)
        v2=password.count(v)
        w2=password.count(w)
        x2=password.count(x)
        y2=password.count(y)
        z2=password.count(z)
        if a==a2:
            lk+=1
        if b==b2:
            lk+=1
        if c==c2:
            lk+=1
        if d==d2:
            lk+=1
        if e==e2:
            lk+=1
        if f==f2:
            lk+=1
        if g==g2:
            lk+=1
        if h==h2:
            lk+=1
        if i==i2:
            lk+=1
        if j==j2:
            lk+=1
        if k==k2:
            lk+=1
        if l==l2:
            lk+=1
        if m==m2:
            lk+=1
        if n==n2:
            lk+=1
        if o==o2:
            lk+=1
        if p==p2:
            lk+=1
        if q==q2:
            lk+=1
        if r==r2:
            lk+=1
        if s==s2:
            lk+=1
        if t==t2:
            lk+=1
        if u==u2:
            lk+=1
        if v==v2:
            lk+=1
        if w==w2:
            lk+=1
        if x==x2:
            lk+=1
        if y==y2:
            lk+=1
        if z==z2:
            lk+=1
        print("likeness=",lk)
    if guss==0:
        print("ADMIN FAILED")
       ```

Answer 1

您为每个单词中都没有出现的字母添加相似性。