python - Unicode解码错误: 'utf-8' codec can't decode byte 0x9d in position 0: invalid start byte when I execute the ` b.decode()`

Question

我有如下代码:

cn_bytes = [157, 188, 156]

cn_str = ""
clen = len(cn_bytes)
count = int(clen / 3)
for x in range(count):
    i = x * 3
    b = bytes([cn_bytes[i], cn_bytes[i + 1], cn_bytes[i + 2]])

    print(b)

    cn_str += b.decode()

当我执行它时，我会收到以下错误:

Traceback (most recent call last):
  File "/Users/dele/Desktop/TestIOS/TestPython/testDemo01/testDemo01/test08.py", line 30, in <module>
    cn_str += b.decode()
UnicodeDecodeError: 'utf-8' codec can't decode byte 0x9d in position 0: invalid start byte

那里说:

UnicodeDecodeError: 'utf-8' codec can't decode byte 0x9d in position 0: invalid start byte

Answer 1

实际上，我认为您无法使用 bytes() 将整个列表转换为字节。但您仍然可以通过迭代各个元素将其转换为字节。

b = [cn_bytes[i], cn_bytes[i + 1], cn_bytes[i + 2]]

cn_str =  [bytes(i)for i in b]