Python 在凯撒密码的暴力破解阶段提供仅可打印 ASCII 字符集 (32-126) 的协助

Question

我试图将暴力破解阶段 (3) 中的解密限制在 ASCII 32 和 ASCII 126 之间。我在前两个阶段已经成功，但在暴力破解期间实现它时遇到了一些麻烦，所以我的结果回来准确。所需的输出是:

*** Menu ***

1. Encrypt string
2. Decrypt string
3. Brute force decryption
4. Quit

What would you like to do [1,2,3,4]? 3

Please enter string to decrypt: ykixkz&yw{oxxkr

Offset: 1 = Decrypted string: xjhwjy%xvznwwjq
Offset: 2 = Decrypted string: wigvix$wuymvvip
Offset: 3 = Decrypted string: vhfuhw#vtxluuho
Offset: 4 = Decrypted string: ugetgv"uswkttgn
Offset: 5 = Decrypted string: tfdsfu!trvjssfm
Offset: 6 = Decrypted string: secret squirrel
Offset: 7 = Decrypted string: rdbqds~rpthqqdk
Offset: 8 = Decrypted string: qcapcr}qosgppcj
Offset: 9 = Decrypted string: pb`obq|pnrfoobi
Offset: 10 = Decrypted string: oa_nap{omqennah

如您所见，它需要生成“ secret 松鼠”。

在暴力破解中，我不知道在哪里实现

for char in stringEncrypt:
        x = ord(char)
        x = x + offsetValue

        while x < 32:
            x += 95
        while x > 126:
            x -= 95  

        total += chr(x)

因此我还可以实现从 ASCII 32 解密为 ASCII 126 的输出。

如有任何帮助，我们将不胜感激。

我尝试将其放入 while 循环中，并将其放在代码中的不同位置。

    print("*** Menu ***")
print(" ")
print("1. Encrypt string")
print("2. Decrypt string")
print("3. Brute force decryption")
print("4. Quit")
print(" ")
selection = int(input("What would you like to do [1,2,3,4]? "))

while selection == 1:
    stringEncrypt = input("Please enter string to encrypt: ")
    offsetValue = int(input("Please enter offset value (1 to 94): "))
    total = ""

    for char in stringEncrypt:
        x = ord(char)
        x = x + offsetValue

        while x < 32:
            x += 95
        while x > 126:
            x -= 95  

        total += chr(x)

    print(" ")
    print("Encrypted string:")
    print(total)


    print(" ")
    print("*** Menu ***")
    print(" ")
    print("1. Encrypt string")
    print("2. Decrypt string")
    print("3. Brute force decryption")
    print("4. Quit")
    print(" ")
    selection = int(input("What would you like to do [1,2,3,4]? "))

while selection == 2:
    stringDecrypt = input("Please enter string to decrypt: ")
    offsetValue = int(input("Please enter offset value (1 to 94): "))
    total = ""

    for char in stringDecrypt:
        x = ord(char)
        x = x - offsetValue

        while x < 32:
            x += 95
        while x > 126:
            x -= 95

        total += chr(x)

    print(" ")
    print("Decrypted string:")
    print(total)


    print(" ")
    print("*** Menu ***")
    print(" ")
    print("1. Encrypt string")
    print("2. Decrypt string")
    print("3. Brute force decryption")
    print("4. Quit")
    print(" ")
    selection = int(input("What would you like to do [1,2,3,4]? "))

while selection == 3:
    stringDecrypt = input("Please enter string to decrypt: ")
    decryptList = list(stringDecrypt)
    offsetValue = 0
    decryptIndex = 0


    for offsetValue in range(1, 95, 1):

    for decryptIndex in range(len(decryptList)):

        shifting = (ord(decryptList[decryptIndex]) - ord(" ") - offsetValue) % 95
        chrDecrypt = chr(shifting + ord(" "))
        decryptList[decryptIndex] = chrDecrypt
        decryptIndex += 1

    stringDecrypt = ''.join(decryptList)

    print("Offset", offsetValue, " = Decrypted string:", stringDecrypt)


    print(" ")
    print("*** Menu ***")
    print(" ")
    print("1. Encrypt string")
    print("2. Decrypt string")
    print("3. Brute force decryption")
    print("4. Quit")
    print(" ")
    selection = int(input("What would you like to do [1,2,3,4]?"))

if selection == 4:
    print("Goodbye.")

我期望输出为输入 ykixkz&yw{oxxkr:

Offset: 1 = Decrypted string: xjhwjy%xvznwwjq
Offset: 2 = Decrypted string: wigvix$wuymvvip
Offset: 3 = Decrypted string: vhfuhw#vtxluuho
Offset: 4 = Decrypted string: ugetgv"uswkttgn
Offset: 5 = Decrypted string: tfdsfu!trvjssfm
Offset: 6 = Decrypted string: secret squirrel
Offset: 7 = Decrypted string: rdbqds~rpthqqdk
Offset: 8 = Decrypted string: qcapcr}qosgppcj
Offset: 9 = Decrypted string: pb`obq|pnrfoobi
Offset: 10 = Decrypted string: oa_nap{omqennah

但我得到:

Offset 1  = Decrypted string: xjhwjy%xvznwwjq
Offset 2  = Decrypted string: vhfuhw#vtxluuho
Offset 3  = Decrypted string: secret squirrel
Offset 4  = Decrypted string: oa_nap{omqennah
Offset 5  = Decrypted string: j\Zi\kvjhl`ii\c
Offset 6  = Decrypted string: dVTcVepdbfZccV]
Offset 7  = Decrypted string: ]OM\O^i][_S\\OV
Offset 8  = Decrypted string: UGETGVaUSWKTTGN
Offset 9  = Decrypted string: L><K>MXLJNBKK>E
Offset 10  = Decrypted string: B42A4CNB@D8AA4;

(最多 94 个)。

Answer 1

请注意解密函数 (x) 和暴力破解函数 (chrDecrypt) 中的字符解密之间的区别。稍后，您无法确保角色是否正确循环。这是条件应该在的位置，基本上确保您在值 32 到 128 上循环。

实现它的一种方法如下:

shifting = (ord(decryptList[decryptIndex]) - ord(" ") - offsetValue) % 95
chrDecrypt = chr(shifting + ord(" "))

这将是所需字符上的移位模块。

为了处理 decryptList 数组的覆盖，您可以执行以下操作:

...
tempDecrypt = []
    for decryptIndex in range(len(decryptList)):

        shifting = (ord(decryptList[decryptIndex]) - ord(" ") - offsetValue) % 95
        chrDecrypt = chr(shifting + ord(" "))
        tempDecrypt.append(chrDecrypt)
        decryptIndex += 1

    stringDecrypt = ''.join(tempDecrypt)
...

这将修复您在之前的代码中注意到的顺序更改。