java - 我可以在 for 循环中对计数器进行异常(exception)处理吗？

Question

我正在尝试编写一个程序，用计算机玩石头、剪刀、布。然而，任务的一部分是让玩家选择与计算机一起玩的回合数。如果出现平局，则该轮不会计入比赛。

我的代码如下所示 - 我更关注程序的 for 部分:

int gamePlays = 0;

for (int = 0; i < gamePlays; i++)
{
 // If, else if, and else statements to make the game possible. 
 // Here is an example of part of the code:
if (cpuChoice.equals ("rock"))
{
  if (userChoice.equals ("scissors"))
  {
      System.out.println("Rock beats scissors, computer wins.");
  }
  else if (userChoice.equals ("paper"))
  {
      System.out.println("Paper beats rock, computer wins.");
  }
  else 
  {
      System.out.println("You both chose rock! It's a tie.");
  }
// The rest would else if cpuChoice.equals "paper" and else. 
}

当最后一个 else 语句与计数器平局时，如何排除它？我已经为此苦苦挣扎了几个小时，但找不到任何解决方案。

Answer 1

我建议使用 while 而不是 for

int i = 0; 
while (i < gamePlays)
{
 // If, else if, and else statements to make the game possible. 
 // Here is an example of part of the code:
if (cpuChoice.equals ("rock"))
{
  if (userChoice.equals ("scissors"))
  {
      System.out.println("Rock beats scissors, computer wins.");
      i++; // increment only when there is result
  }
  else if (userChoice.equals ("paper"))
  {
      System.out.println("Paper beats rock, computer wins.");
      i++; // increment only when there is result
  }
  else 
  {
      System.out.println("You both chose rock! It's a tie.");
     // don't increment if no result
   }
// The rest would else if cpuChoice.equals "paper" and else. 
}

}