Java时间转换

Question

Scanner input2 = new Scanner(System.in);
System.out.println("Time to be converted to hh:mm:ss: ");
int time = input2.nextInt();
int hr = 0, min = 0, sec = 0;
if(time >= 3600)
{
   hr = time/3600;
   time = time%3600;
}
if(time >= 60)
{
    time = time%3600;
    min = time/60;
}
if (time <  60)
{
    sec  +=  time;
}
System.out.println(hr+":"+min+":"+sec);

所以，我的问题是，只要秒大于 3719，分钟和小时就停止递增。

示例:

3719
1:1:59

3720
1:1:0

7325
1:1:0

我还尝试了一种不同的算法，使用减法而不是模

Scanner input2 = new Scanner(System.in);
System.out.println("Time to be converted to hh:mm:ss: ");
int time = input2.nextInt();
int hr = 0, min = 0, sec = 0;
if(time >= 3600)
{
   hr ++;
   time -=3600;
}
if(time >= 60)
{
    time -= 60;
    min ++;
}
if (time <  60)
{
    sec  +=  time;
}
System.out.println(hr+":"+min+":"+sec);

Answer 1

这是因为您使用 3600 作为 min 的模数:

if (time >= 60) {
    min = time / 60;
    time = time % 3600;
}

但必须使用60，将其更改为:

public static void main(String[] args) {
    Scanner input2 = new Scanner(System.in);
    System.out.println("Time to be converted to hh:mm:ss: ");
    int time = input2.nextInt();
    int hr = 0, min = 0, sec = 0;
    if (time >= 3600) {
        hr = time / 3600;
        time = time % 3600;
    }
    if (time >= 60) {
        min = time / 60;
        time = time % 60;
    }
    if (time < 60) {
        sec += time;
    }
    System.out.println(hr + ":" + min + ":" + sec);
}

它会按照你的预期工作。

在这里查看http://ideone.com/unTQTW