python - 如何添加以 : ('name' , 形式给出的元组列表给出的数字(数字)

Question

def Highest_n_scores(分数, n = 5):

每个玩家都会玩游戏一定次数，每次都会生成一个元组(名称、分数)，表示该玩家在游戏中的得分。给定以此类元组列表形式进行的所有游戏，将每个玩家的 n 个最高分数相加作为该玩家的总分数。创建并返回一个列表，其中包含玩家的元组(名称、总分)及其总分数，按名称升序排序。如果某个玩家玩的次数少于 n 次，则只需将该玩家玩过的所有游戏的得分相加即可。

代码如下，但我想知道是否有更有效的方法来执行此操作，并且使用测试器似乎也不起作用。

def highest_n_scores(scores, n):

    bill = sorted([p for (t,p) in scores if t == 'bill'])
    jack = sorted([p for (t,p) in scores if t == 'jack'])
    sheldon = sorted([p for (t,p) in scores if t == 'sheldon'])
    tina = sorted([p for (t,p) in scores if t == 'tina'])
    amy = sorted([p for (t,p) in scores if t == 'amy'])
    bob = sorted([p for (t,p) in scores if t == 'bob'])

    scoreBill = sum(bill[-n:])
    scoreJack = sum(jack[-n:])
    scoreSheldon = sum(sheldon[-n:])
    scoreTina = sum(tina[-n:])
    scoreAmy = sum(amy[-n:])
    scoreBob = sum(bob[-n:])

    return sorted([('bill', scoreBill), ('jack', scoreJack), ('sheldon', scoreSheldon), ('tina', scoreTina), ('amy', scoreAmy), ('bob', scoreBob)])

我得到了正确的结果，但是所有值的测试人员都告诉我，测试代码的测试人员说我的答案是错误的。

列表:

[('bill', 10), ('jack', 6), ('sheldon', 3), ('tina', 2), ('amy', 3), ('sheldon', 6), ('tina', 7), ('jack', 2), ('bob', 3), ('bob', 4), ('bill', 3), ('bill', 9), ('sheldon', 5), ('amy', 2), ('jack', 7), ('sheldon', 5), ('sheldon', 7), ('bill', 1), ('bill', 9), ('sheldon', 5), ('bill', 2), ('bill', 6), ('jack', 6), ('bob', 4), ('tina', 5), ('sheldon', 4), ('sheldon', 2), ('amy', 6), ('bob', 7), ('jack', 2), ('bob', 5), ('sheldon', 9), ('jack', 5), ('amy', 9), ('bob', 7), ('tina', 6), ('tina', 2), ('amy', 7), ('jack', 10), ('tina', 4), ('bob', 5), ('jack', 10), ('bob', 7), ('jack', 5), ('amy', 4), ('amy', 8), ('bob', 4), ('bill', 8), ('bob', 6), ('tina', 6), ('amy', 9), ('bill', 4), ('jack', 2), ('amy', 2), ('amy', 4), ('sheldon', 1), ('tina', 3), ('bill', 9), ('tina', 4), ('tina', 9)] when n = 3

列表返回:

[('amy', 26), ('bill', 28), ('bob', 21), ('jack', 27), ('sheldon', 22), ('tina', 22)]

Answer 1

您当前正在创建与名称一样多的变量，这不是很高效且可扩展，您可以考虑使用字典来存储您的信息

您可以首先收集字典中的所有分数，将键作为名称，将值作为分数列表。然后，您迭代字典，对于每个名称，按降序对分数进行排序，并找到前 n 个元素的总和。

代码如下所示:

scores = [('bill', 10), ('jack', 6), ('sheldon', 3), ('tina', 2), ('amy', 3), ('sheldon', 6), ('tina', 7), ('jack', 2), ('bob', 3), ('bob', 4), ('bill', 3), ('bill', 9), ('sheldon', 5), ('amy', 2), ('jack', 7), ('sheldon', 5), ('sheldon', 7), ('bill', 1), ('bill', 9), ('sheldon', 5), ('bill', 2), ('bill', 6), ('jack', 6), ('bob', 4), ('tina', 5), ('sheldon', 4), ('sheldon', 2), ('amy', 6), ('bob', 7), ('jack', 2), ('bob', 5), ('sheldon', 9), ('jack', 5), ('amy', 9), ('bob', 7), ('tina', 6), ('tina', 2), ('amy', 7), ('jack', 10), ('tina', 4), ('bob', 5), ('jack', 10), ('bob', 7), ('jack', 5), ('amy', 4), ('amy', 8), ('bob', 4), ('bill', 8), ('bob', 6), ('tina', 6), ('amy', 9), ('bill', 4), ('jack', 2), ('amy', 2), ('amy', 4), ('sheldon', 1), ('tina', 3), ('bill', 9), ('tina', 4), ('tina', 9)]

def highest_n_scores(scores, n = 5):

    scores_dict = {}

    #Make a dictionary of name to list of scores
    for name, score in scores:
        #Set the default value of the dict as an empty list
        scores_dict.setdefault(name, [])
        #Append the score to the name
        scores_dict[name].append(score)

    result_list = []

    #Iterate over the dictionary
    for name, score in scores_dict.items():

        #For total score, sort the list in descending order, and take the sum of first n elements
        total_score = sum(sorted(score, reverse=True)[:n])
        result_list.append((name, total_score))

    return result_list

print(highest_n_scores(scores, 3))

输出将是

[('bill', 28), ('jack', 27), ('sheldon', 22), ('tina', 22), ('amy', 26), ('bob', 21)]