Python:如何从两个文件创建一个哈希值

Question

我正在寻找从两个文件创建哈希，但不知道如何做。

我可以使用以下代码一次对一个文件进行哈希处理。

#functions: create sha384 hash
def create_hash(folder, filename):
    BLOCKSIZE = 65536
    hasher = hashlib.sha384()
    with open(folder + filename, 'rb') as afile:
        buf = afile.read(BLOCKSIZE)
        while len(buf) > 0:
            hasher.update(buf)
            buf = afile.read(BLOCKSIZE)
    #print(hasher.hexdigest())
    return BLOCKSIZE, hasher

BLOCKSIZE, hasher = create_hash(ARCHIVE_FOLDER, ARCHIVE_FILENAME)

理想情况下，我想对此进行调整，以便它需要两个文件并生成两个文件的一个哈希值？不确定这是否真的可能。

编辑:我已更新代码如下。它运行了，但我只得到以下输出，我不知道为什么。大家有什么见解吗？

combined: built-in method hexdigest of _hashlib.HASH object at 0x000001DFFC9929B8

#functions: create sha384 hash
def create_hash2(folder, filename1, filename2):
    BLOCKSIZE = 65536
    hasher = hashlib.sha384()
    with open(folder + filename1, 'rb') as afile, open(folder + filename2, 'rb') as bfile:
        buf = afile.read(BLOCKSIZE) and bfile.read(BLOCKSIZE)
        while len(buf) > 0:
            hasher.update(buf)
            buf = afile.read(BLOCKSIZE) and bfile.read(BLOCKSIZE)
    #print(hasher.hexdigest())
    return BLOCKSIZE, hasher

        #test
        BLOCKSIZE, hasher = create_hash2(ARCHIVE_FOLDER, '1--2019-06-13-archive.zip', '2--2019-06-13-archive.zip')
        print('combined: ' + str(hasher.hexdigest))

Answer 1

您可以循环遍历文件:

def create_hash(folder, filenames):  # takes an arbitrary number of filenames
    BLOCKSIZE = 65536
    hasher = hashlib.sha384()
    for filename in filenames:
        with open(folder + filename, 'rb') as afile:
            buf = afile.read(BLOCKSIZE)
            while len(buf) > 0:
                hasher.update(buf)
                buf = afile.read(BLOCKSIZE)
    return BLOCKSIZE, hasher

BLOCKSIZE, hasher = create_hash(ARCHIVE_FOLDER, (ARCHIVE_FILENAME_1, ARCHIVE_FILENAME_2))

请注意，提供文件名的顺序很重要(即，如果交换两个文件名，哈希值几乎肯定会不同)。