Java:使用扫描仪读取 boolean 值失败。

Question

import java.util.Scanner;

public class Cardhelp2{

private static String[] pairArray={"A,A","K,K","Q,Q","J,J","10,10","9,9","8,8","7,7","6,6","5,5","4,4","3,3","2,2"};

public static void generateRandom(int k){
 int minimum = 0;
 int maximum = 13;
 for(int i = 1; i <= k; i++)
   {
     int randomNum = minimum + (int)(Math.random()* maximum);
     System.out.print("Player " + i +" , You have been dealt a pair of: ");
     System.out.println(pairArray[randomNum]);
   }
} //reads array and randomizes cards

 public static void main(String[] args) {
 Scanner scan = new Scanner(System.in);
 System.out.print("How many players would you like to play with? ");
 int m = scan.nextInt();
 generateRandom(m);

//displays the cards

___________________________________________________
System.out.println("Would you like to play?");
 Scanner scanner = new Scanner(System.in);

 if(scanner.next().equalsIgnoreCase("y")||scanner.next().equalsIgnoreCase("yes")) {
System.out.println("This will be fun");
} else if(scanner.next().equalsIgnoreCase("n")||scanner.next().equalsIgnoreCase("no")) {
System.out.println("Maybe next time");
} else { 
System.out.println("Invalid character");

 }
 }
}

我无法理解为什么最后部分不起作用，我被告知我需要更改scanner.next();到一个变量，但我不知道如何做到这一点并使代码正常工作。有没有一种简单的方法可以读取用户的答案，然后向用户显示响应？

谢谢

Answer 1

你的条件表达式

if(scanner.next().equalsIgnoreCase("y")||scanner.next().equalsIgnoreCase("yes")) 

调用 scanner.next() 两次，这意味着第二次调用将读取/等待更多输入。相反，您只需调用它一次，存储结果并在比较中使用它:

String tmp = scanner.next();
if(tmp.equalsIgnoreCase("y")||tmp.equalsIgnoreCase("yes"))