java - 将十六进制字符串解析为 int 值时出现意外的 NumberFormatException

Question

我想解析一个包含 8 个十六进制数字(4 个字节)的字符串，但出现 NumberFormatException。这里出了什么问题？

assertThat(Integer.parseInt("FFFF4C6A",16),is(0xFFFF4C6A));

Answer 1

您的数字代表的数字大于可分配给 int 的数字。尝试:

Long.parseLong("FFFF4C6A", 16);

给出 4294921322。

来自doc :

An exception of type NumberFormatException is thrown if any of the following situations occurs:

• The first argument is null or is a string of length zero.
• The radix is either smaller than Character.MIN_RADIX or larger than Character.MAX_RADIX.
• Any character of the string is not a digit of the specified radix, …
• The value represented by the string is not a value of type int.

这是您遇到的第四个案例。