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python - 使用 ccrs.epsg() 使用 EPSG 4326 坐标系绘制邮政编码周长形状文件

转载 作者:行者123 更新时间:2023-12-01 07:34:56 29 4
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我从 here 获得了邮政编码周长的 shapefile并想将它们绘制在 Cartopy map 上,就像我在 this example 中所做的那样.

根据消息来源,该数据采用 EPSG 4326 坐标系。当我尝试绘制数据时

import matplotlib.pyplot as plt
import cartopy.crs as ccrs
import cartopy.io.img_tiles as cimgt
from cartopy.io.shapereader import Reader
from cartopy.feature import ShapelyFeature

# Create a Stamen terrain background instance
stamen_terrain = cimgt.Stamen('terrain-background')
fig = plt.figure(figsize = (mapsize,mapsize))
ax = fig.add_subplot(1, 1, 1, projection=stamen_terrain.crs)

# Set range of map, stipulate zoom level
ax.set_extent([-122.7, -121.5, 37.15, 38.15], crs=ccrs.Geodetic())
ax.add_image(stamen_terrain, 8, zorder = 0)

# Add city borders
shape_feature = ShapelyFeature(Reader(shapefile).geometries(), ccrs.epsg(4326),
linewidth = 2, facecolor = (1, 1, 1, 0),
edgecolor = (0.3, 0.3, 0.3, 1))
ax.add_feature(shape_feature, zorder = 1)

我看到以下错误:

ValueError: EPSG code does not define a projection

可能相关 - 当我查看 ccrs.epsg() 函数时,它表示不支持此 EPSG 代码

help(ccrs.epsg)
Help on function epsg in module cartopy.crs:

epsg(code)
Return the projection which corresponds to the given EPSG code.

The EPSG code must correspond to a "projected coordinate system",
so EPSG codes such as 4326 (WGS-84) which define a "geodetic coordinate
system" will not work.

Note
----
The conversion is performed by querying https://epsg.io/ so a
live internet connection is required.

鉴于这个结果,我还尝试使用ccrs.Geodetic():

# Add city borders
shape_feature = ShapelyFeature(Reader(shapefile).geometries(), ccrs.Geodetic(),
linewidth = 2, facecolor = (1, 1, 1, 0),
edgecolor = (0.3, 0.3, 0.3, 1))
ax.add_feature(shape_feature, zorder = 1)

但这也无法显示邮政编码周界,并显示此警告消息:

UserWarning: Approximating coordinate system <cartopy._crs.Geodetic object at 0x1a2d2375c8> with the PlateCarree projection.
'PlateCarree projection.'.format(crs))

我也尝试过ccrs.PlateCarree(),但没有运气。请帮忙!

最佳答案

要将不同来源的数据绘制在一起,必须为每个数据集声明正确的坐标引用系。对于 shapefile,您可以在其随附的 xxx.prj 文件中找到它。

这是工作代码:

import cartopy.io.img_tiles as cimgt 
from cartopy.io.shapereader import Reader
from cartopy.feature import ShapelyFeature
import cartopy.crs as ccrs
import matplotlib.pyplot as plt

shapefile_name= "./data/ZIPCODE.shp"
mapwidth, mapheight = 8, 8
pad = 0.25

stamen_terrain = cimgt.Stamen('terrain-background')
stm_crs = stamen_terrain.crs

fig = plt.figure(figsize = (mapwidth, mapheight))
ax = fig.add_subplot(1, 1, 1, projection=stm_crs) #world mercator

# Set extent of map
ax.set_extent([-123.3-pad, -121.5+pad, 37.05-pad, 38.75+pad], crs=ccrs.Geodetic())
# Plot base map
ax.add_image(stamen_terrain, 8, zorder=0)

# Add polygons from shapefile
# Note: the use of `ccrs.epsg(26910)`
shape_feature = ShapelyFeature(Reader(shapefile_name).geometries(), ccrs.epsg(26910))

# You can choose one of the 2 possible methods to plot
# ... the geometries from shapefile
# Styling is done here.
method = 1
if method==1:
# iteration is hidden
ax.add_feature(shape_feature, facecolor='b', edgecolor='red', alpha=0.4, zorder = 15)
if method==2:
# iterate and use `.add_geometries()`
# more flexible to manipulate particular items
for geom in shape_feature.geometries():
ax.add_geometries([geom], crs=shape_feature.crs, facecolor='b', edgecolor='red', alpha=0.4)

plt.show()

输出图:

enter image description here

关于python - 使用 ccrs.epsg() 使用 EPSG 4326 坐标系绘制邮政编码周长形状文件,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/57030906/

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