从命令行运行时Python不创建文件

Question

我创建了一个 python 脚本来清理 csv 文件。脚本文件“CleanCSV.py”中的代码如下

import csv

filepath_i = 'C:\Source Files\Data Source\Flat File Source\PatientRecords.csv'
filepath_o = 'C:\Python\PatientRecords.csv'
rows = []
with open(filepath_i, 'r', newline='') as csv_file:
    csv_reader = csv.reader(csv_file, delimiter=',', quotechar='"')
    with open(filepath_o, 'w', newline='' ) as writeFile:
        writer = csv.writer(writeFile, lineterminator='\r')
        for row in csv_reader:
            row[3] = row[3].replace("\n","").replace("\r","") 
            rows.append(row) 
        writer.writerows(rows)

从 python 编辑器运行时工作正常。但从命令行运行时不会创建文件，如下所示。

C:\Program Files (x86)\Microsoft Visual Studio\Shared\Python36_64>python C:\Python\CleanCSV.py 

我也尝试过这个

C:\Program Files (x86)\Microsoft Visual Studio\Shared\Python36_64>pythonw C:\Python\CleanCSV.pyw 

我提供了对文件夹的完全访问权限，但仍然没有在目标位置创建任何文件。如果我遗漏了什么，请告诉我。

还请建议是否可以优化此代码。我不能使用像 pandas 这样的外部包，所以我用 csv 来做。提前致谢。

Extension

当我将写入设置更改为 x 时

with open(filepath_o, 'x', newline='' ) as writeFile:

令我惊讶的是我收到了这个错误

File "CleanCSV.py", line 8, in <module>
    with open(filepath_o, 'x', newline='' ) as writeFile:
FileExistsError: [Errno 17] File exists: 'C:\\Python\\PatientRecords1.csv'

但我在目录中没有看到该文件。即使将隐藏文件设置为 true 后也是如此。所以我运行了这个脚本。

from pathlib import Path
config = Path(filepath_o )
if config.is_file():
    print('yes')
    print(config)
else:
    print('no')

得到这个输出，但是目录中没有文件!!困惑。

yes
C:\Python\PatientRecords1.csv

Extension 2

重写脚本以尝试使用目录

with open(filepath_i,'r') as csv_file:
    csv_reader = csv.DictReader(csv_file, delimiter=',', quotechar='"')

    with open('PatientRecords1.csv', 'w') as writeFile:
        fieldnames = ['DRG Definition','Provider Id','Provider Name','Provider Street Address','Provider City','Provider State','Provider Zip Code','Hospital Referral Region Description','Hospital Category','Hospital Type', 'Total Discharges' ,'Covered Charges' , 'Total Payments' ,'Medicare Payments']
        writer = csv.DictWriter(writeFile,fieldnames=fieldnames)
        for row in csv_reader:
            row['Provider Street Address'] = row['Provider Street Address'].replace("\n","").replace("\r","") 
            writer.writerows(row)

但收到此错误

Traceback (most recent call last):
  File "CleanCSV.py", line 36, in <module>
    writer.writerows(row)
  File "C:\Program Files (x86)\Microsoft Visual Studio\Shared\Python36_64\lib\csv.py", line 158, in writerows
    return self.writer.writerows(map(self._dict_to_list, rowdicts))
  File "C:\Program Files (x86)\Microsoft Visual Studio\Shared\Python36_64\lib\csv.py", line 148, in _dict_to_list
    wrong_fields = rowdict.keys() - self.fieldnames
AttributeError: 'str' object has no attribute 'keys'

示例输入文件数据

DRG Definition,Provider Id,Provider Name,Provider Street Address,Provider City,Provider State,Provider Zip Code,Hospital Referral Region Description,Hospital Category,Hospital Type, Total Discharges ,Covered Charges , Total Payments ,Medicare Payments
039 - EXTRACRANIAL PROCEDURES W/O CC/MCC,10001,SOUTHEAST ALABAMA MEDICAL CENTER,1108 ROSS CLARK CIRCLE,DOTHAN,AL,36301,AL - Dothan,Specialty Centers,Government Funded,91,"$32,963.07 ","$5,777.24 ","$4,763.73 "
039 - EXTRACRANIAL PROCEDURES W/O CC/MCC,10005,MARSHALL MEDICAL CENTER SOUTH,"2505 U S HIGHWAY 
431 NORTH",BOAZ,AL,35957,AL - Birmingham,Specialty Centers,Private Institution,14,"$15,131.85 ","$5,787.57 ","$4,976.71 "
039 - EXTRACRANIAL PROCEDURES W/O CC/MCC,10006,ELIZA COFFEE MEMORIAL HOSPITAL,205 MARENGO STREET,FLORENCE,AL,35631,AL - Birmingham,Rehabilitation Centers,Private Institution,24,"$37,560.37 ","$5,434.95 ","$4,453.79 "

Extension 3

看起来文件是在目录中创建的，我得到了这两段代码的输出。但是我看不到该文件，想知道为什么!

with open(filepath_o,'r') as csv_file:
    csv_reader = csv.reader(csv_file, delimiter=',', quotechar='"')
    for row in csv_reader:
        print(row)

import os.path 
from os import path
print(path.exists(filepath_o ))

Answer 1

转到 python 脚本所在的位置。单击文件夹的地址栏并输入 cmd

然后将从脚本的文件夹位置启动命令提示符

然后输入cmd

python CleanCSV.py

注意:您需要将 python 添加到环境变量中。

<小时/>

如果您使用的是 Anaconda，请按照上述 Anaconda Prompt 中提到的步骤进行操作。