java - 直角三角形计算返回0？

Question

我不知道我在这里做错了什么。我刚刚写了一个类似的代码，运行得很好。一旦我掌握了如何使用扫描仪类。我正在开发一个程序，该程序获取直角三角形的高度和底边，然后计算周长、面积和斜边。但它为每个方法返回 0.0，我无法弄清楚我是否缺少某种语法，或者我是否真的搞乱了我的计算。有人可以指出我错误的正确方向吗？

    public class RightTriangle {

    private double height;
    private double base;
    private final double hypotenuse = Math.sqrt(Math.pow(height, 2) + Math.pow(base, 2));

   public RightTriangle(double triHeight, double triBase)
   {
       triHeight = height;
       triBase = base;
   }

   public double getPerimeter()
   {
       double perimeter = height + base + hypotenuse;
       return perimeter;
   }

   public double getArea()
   {
       double area = (height + base) / 2;
       return area;
   }

   public double getHypotenuse()
   {
       return hypotenuse;
   }
}

这是我的主要方法:

    import java.util.Scanner;

    public class CalculateTriangle 
{

    public static void main(String[] args)
    {
        Scanner triangleHeight = new Scanner(System.in);
        System.out.print("Enter Triangle Height: ");
        double height = triangleHeight.nextDouble();

        Scanner triangleBase = new Scanner(System.in);
        System.out.print("Enter Triangle Base: ");
        double base = triangleBase.nextDouble();

        RightTriangle newTriangle = new RightTriangle(height, base);

        newTriangle.getPerimeter();
        double perimeter = newTriangle.getPerimeter();

        newTriangle.getArea();
        double area = newTriangle.getArea();

        newTriangle.getHypotenuse();
        double hypotenuse = newTriangle.getHypotenuse();

        System.out.println(perimeter);
        System.out.println(area);
        System.out.println(hypotenuse);

    }
}

Answer 1

您的代码:

public RightTriangle(double triHeight, double triBase)
{
   triHeight = height;
   triBase = base;
}

应该是:

public RightTriangle(double triHeight, double triBase)
{
   height = triHeight;
   base = triBase;
}