python - 如何每次检查用户输入的内容与数组[i]中的内容相同时将分数增加100？

Question

我正在尝试创建一个游戏，用户必须记忆弹出窗口中显示的数字。如果他们犯错了，“不正确”就会随着犯错的数字数量而增加。如果他们答对了每个数字，分数就会增加 100。在这种情况下，应该输出 300 作为分数。如果用户输入的内容与 array[i]

相同，则分数只能增加 100

import random

array = []

#this appends three random numbers into an empty array
for i in range(3):
    randomNumber = random.randint(0,100)
    array.append(randomNumber)

# this function displays the random number for 1250 milliseconds
def randomNumberDisplay():
    import tkinter as tk
    root = tk.Tk()
    root.title("info")
    tk.Label(root, text=array).pack()
    # time in ms
    root.after(1250, lambda: root.destroy())
    root.mainloop()   
randomNumberDisplay()


#this function requires the user to enter the numbers displayed.
score = 0
def levelOne ():
    incorrect = 0
    i = 0
    x = len(array)

for i in range (3):
    userNumber = int(input("please enter the numbers you saw IN ORDER(press Enter when finished): "))

    #if they enter the right number, they gain a score and get to move to the next level
    while userNumber != array[i]:
        print ("the numbers where: ", array[i])
        incorrect = incorrect +1
        ("you got ", incorrect, "wrong")

    if userNumber == array[i]:
        score = correct + 100
        i = i + 1
    print ("you have ",score, "points")
levelOne ()

玩游戏时显示的示例:

请按顺序输入您看到的数字(完成后按 Enter):58

请按顺序输入您看到的数字(完成后按 Enter):84

请按顺序输入您看到的数字(完成后按 Enter):44

您有 100 分

Answer 1

1. 您尚未初始化变量“不正确”。它将抛出一个 NameError。

2. 不需要 while 循环。将“while”替换为“if”语句。

3. 分数 = 分数 + 1。那里不需要正确的变量。 (除非你想告诉玩家他们答对了多少个数字。在这种情况下，初始化正确= 0。然后每次玩家的答案正确时增加正确的计数:正确+= 1。

4. 无需使用第二个“if”语句来检查用户是否输入了正确的数字，只需使用“else”语句即可。

这是固定代码:

    import random
    array = []

    #this appends three random numbers into an empty array
    for i in range(3):
        randomNumber = random.randint(0,100)
        array.append(randomNumber)

    # this function displays the random number for 1250 milliseconds
    def randomNumberDisplay():
        import tkinter as tk
        root = tk.Tk()
        root.title("info")
        tk.Label(root, text=array).pack()
        # time in ms
        root.after(1250, lambda: root.destroy())
        root.mainloop()   
    randomNumberDisplay()


    #this function requires the user to enter the numbers displayed.
    score = 0
    def levelOne ():
        incorrect = 0
        x = len(array)
        incorrect = 0
        for i in range (3):
            userNumber = int(input("please enter the numbers you saw IN ORDER(press Enter when finished): "))

        #if they enter the right number, they gain a score and get to move to the next level
        if userNumber != array[i]:
            print ("the numbers where: ", array[i])
            incorrect = incorrect +1
            print("you got ", incorrect, "wrong")

        else:
            score = score + 100
            i = i + 1
            print ("you have ",score, "points")
    levelOne ()