python - 如何在函数式Python中将数组转换为int

Question

我从用户输入到数组制作了一个素数检测器，但我无法将数组转换为 int 来检测每个数字

n = int(input("Enter number of elements : "))
a = list(map(int,input("\nEnter the numbers : ").strip().split()))[:n]

def isPrimer(a):
    Prime = True
    if n >= 2:
        if a % n == 0 :
            Prime = False
    else:
        Prime = False
    return Prime

print(isPrimer(a))

这是我的输出:

输入元素数量:3

输入数字:10 11 12

Traceback (most recent call last):
  File "/Users/firmanpraadita/PycharmProjects/PemFungsional/kegiatan_1.py", line 13, in <module>
    print(isPrimer(a))
  File "/Users/firmanpraadita/PycharmProjects/PemFungsional/kegiatan_1.py", line 8, in isPrimer
    if a % n == 0 :
TypeError: unsupported operand type(s) for %: 'list' and 'int'

Answer 1

您需要迭代列表:

n = int(input("Enter number of elements : "))
a = list(map(int,input("\nEnter the numbers : ").strip().split()))[:n]

def isPrimer(a):
    Prime = True
    if n >= 2:
        if a % n == 0 :
            Prime = False
    else:
        Prime = False
    return Prime

for item in a:
    print(isPrimer(item))