java - Java 有 isSomething() 库吗？

Question

很难说出这里问的是什么。这个问题是含糊的、模糊的、不完整的、过于宽泛的或修辞性的，无法以目前的形式得到合理的回答。如需帮助澄清此问题以便重新打开它， visit the help center 。

已关闭 12 年前。

我想知道是否有一个 Java 库，其实现如下:isTemperature() , isPercentual() , isDistanceUnit() , isWeightUnit() , isProperName() , isDate() , isYear() , isPhone() , isLocation()以及还可以定义什么。

不仅单位符合我的兴趣，而且所有可以进行的分类类型，无论是数字还是单词。

这将用于对文本中的单词进行分类。

Answer 1

据我所知，没有。但是，您仍然可以自己创建执行相同操作的方法...

isTemperature()

boolean isTemperature(String check) {
    char[] letters = check.toCharArray();
    if (check.indexOf("°").equals((letters.length - 1)) {
        return true;
    }
    return false;
}

isPercentual()

boolean isPercentual(String check) {
    try {
        double verify = Double.parseDouble(check);
    } catch (NumberFormatException e) {
        return false;
    }
    char[] numbers = check.toCharArray();
    if (check.indexOf("%").equals(numbers.length) {
        return true;
    }
    return false;
}

isDistanceUnit()

boolean isDistanceUnit(String check, boolean customary) {
    String[] customaryUnits = {"mi","yd","ft","in"};
    String[] metricUnits = {"mm","cm","dm","m","km"};
    if (customary) {
        for (int i = 0; i <= customaryUnits.length; i++) {
            if (check.toLowerCase().contains(customaryUnits[i])) {
                return true;
            }
        }
        return false;
    } else {
        for (int i = 0; i <= metricUnits.length; i++) {
            if (check.toLowerCase().contains(metricUnits[i])) {
                return true;
            }
        }
        return false;
    }
}

isWeightUnit()

boolean isWeightUnit(String check, boolean customary) {
    String[] customaryUnits = {"lb","oz","T"};
    String[] metricUnits = {"kg"}; //I'm sorry that's all I know :(
    if (customary) {
        for (int i = 0; i <= customaryUnits.length; i++) {
            if (check.toLowerCase().contains(customaryUnits[i])) {
                return true;
            }
        }
        return false;
    } else {
        for (int i = 0; i <= metricUnits.length; i++) {
            if (check.toLowerCase().contains(metricUnits[i])) {
                return true;
            }
        }
        return false;
    }
}

isProperName()

boolean isProperName(String check) {
    char[] letters = check.toCharArray();
    String[] capLetters = {"A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"};
    for (int i = 0; i <= capLetters.length; i++) {
        if (letters[0].equals(capLetters[i])) {
            return true;
        }
    }
    return false;
}

isDate()

更新:现在我可以给你这个。不过，在我这样做之前，请先简要说明一下。在代码开头添加这些行，否则此方法将不起作用。

import java.text.SimpleDateFormat;
import java.text.ParseException;
//--------------------------------------------------------------------------------
boolean isDate(String check) {
    SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd");
    if (check.trim().length != dateFormat.toPattern().length) {
        return false;
    }
    dateFormat.setLenient(false);
    try {  
        dateFormat.parse(check.trim());
    } catch (ParseException pe) {
        return false;
    }
    return true;
}

isYear()

boolean isYear(String check) {
    try {
        int verify = Integer.parseInt(check);
    } catch (NumberFormatException e) {
        return false;
    }
    char[] verify2 = check.toCharArray();
    if ((verify2.length).equals(4)) {
        return true;
    }
    return false;
}

isPhone()

您还没有真正说出您要检查哪种电话号码。我猜您想要这种形式的一份 (865-867-5309)。

boolean isPhone(String check) {
    float firstHyphen = check.indexOf("-");
    char[] numbers = check.toCharArray();
    float check2 = numbers.length / 3;
    if (firstHypen.equals(check2)) {
        return true;
    }
    return false;
}

isLocation()

很抱歉我现在不能给你这个。 :(

isEmail()

boolean isEmail(String check) {
    String[] emailDomains = {".com",".net",".org"};
    String[] emailProviders = {"gmail","yahoo","hotmail","aol","tds","comcast","charter","peoplepc"}; //add more if you want
    char[] check2 = check.toCharArray();
    for (int i = 0; i <= emailProviders.length; i++) {
        for (int x = 0; x <= emailDomains.length; x++) {
            if ((check.indexOf(emailDomains[x]).equals(check2.length)) && (check.indexOf(emailProviders[i]).equals(check2.length - emailDomains[x].toCharArray().length)) {
            return true;
            }
        }
    }
    return false;
}

<小时/>

如果您愿意，您可以为 isDistanceUnit() 和 isWeightUnit() 方法添加更多单位。如果您需要更多方法或有任何疑问，请询问。 :)