php - JQuery $.post() 问题，没有执行任何操作

Question

我的 jQuery 函数遇到一个小问题，下面是代码:

function registerUser()
{
    var formData = $('#registerForm').serialize();
    var dataPost = $.post('classes/login.php', {type:'register', data: formData} ,function (data)
    {
        console.log(data);
    });
};

然后我的 login.php 文件如下所示:

$type = $_POST['type'];
$email = $_POST['data']['0'];
$password = $_POST['data']['1'];

function register_user($email, $password)
{
 global $db;
//lets add some code to register user
    $stmt = $db->prepare("INSERT INTO user (email, password, role, banned) VALUES (:email, :password, 'level1', 'N')");
    $stmt->execute(array(':email'=> $email, ':password'=> $password));
    $rowCount  = $stmt->rowCount();
   if($rowCount > 0)
   {
    // Success
    //  set session data and etc.
    return "success";
   }
   else
   {
    //  Failed
    return "Error, please try again!";
   }
}
$result = register_user($email, $password);

当我执行它时，我没有收到任何错误或任何其他信息，只是一个简单的空白行不显示任何数据，并且数据没有插入到数据库中？

Answer 1

您想要通过表单序列化发布额外参数。

function registerUser()
{
    var formData = $('#registerForm').serializeArray();
    formData.push({name: 'type', value: 'register'});
    var dataPost = $.post('classes/login.php', formData ,function (data)
    {
        console.log(data);

    });
};

现在服务器端更新

$type = $_POST['type'];
$email = $_POST['LoginEmail'];
$password = $_POST['LoginPassword'];

function register_user($email, $password)
{
 global $db;
//lets add some code to register user
    $stmt = $db->prepare("INSERT INTO user (email, password, role, banned) VALUES (:email, :password, 'level1', 'N')");
    $stmt->execute(array(':email'=> $email, ':password'=> $password));
    $rowCount  = $stmt->rowCount();
   if($rowCount > 0)
   {
    // Success
    //  set session data and etc.
    return "success";
  }
  else
  {
//  Failed
    return "Error, please try again!";
  }
}
$result = register_user($email, $password);

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