scala - 将前导零添加到 Spark 数据帧中的列

Question

这个问题在这里已经有了答案:





Prepend zeros to a value in PySpark

(2 个回答)


3年前关闭。




简而言之，我正在利用 spark-xml 对 XML 文件进行一些解析。但是，使用它会删除我感兴趣的所有值中的前导零。但是，我需要最终输出，它是一个 DataFrame，以包含前导零。我不确定/无法想出一种向我感兴趣的列添加前导零的方法。

val df = spark.read
  .format("com.databricks.spark.xml")
  .option("rowTag", "output")
  .option("excludeAttribute", true)
  .option("allowNumericLeadingZeros", true) //including this does not solve the problem
  .load("pathToXmlFile")

我得到的示例输出

+------+---+--------------------+
|iD    |val|Code                |
+------+---+--------------------+
|1     |44 |9022070536692784476 |
|2     |66 |-5138930048185086175|
|3     |25 |805582856291361761  |
|4     |17 |-9107885086776983000|
|5     |18 |1993794295881733178 |
|6     |31 |-2867434050463300064|
|7     |88 |-4692317993930338046|
|8     |44 |-4039776869915039812|
|9     |20 |-5786627276152563542|
|10    |12 |7614363703260494022 |
+------+---+--------------------+

期望输出

+--------+----+--------------------+
|iD      |val |Code                |
+--------+----+--------------------+
|001     |044 |9022070536692784476 |
|002     |066 |-5138930048185086175|
|003     |025 |805582856291361761  |
|004     |017 |-9107885086776983000|
|005     |018 |1993794295881733178 |
|006     |031 |-2867434050463300064|
|007     |088 |-4692317993930338046|
|008     |044 |-4039776869915039812|
|009     |020 |-5786627276152563542|
|0010    |012 |7614363703260494022 |
+--------+----+--------------------+

Answer 1

这为我解决了，谢谢大家的帮助

 val df2 = df
        .withColumn("idLong", format_string("%03d", $"iD"))