java - Java中的静态方法

Question

查看一些 java 代码，这似乎不对。对我来说，看起来每次你调用projects时，你都会得到一个新的hashmap，所以这个说法总是错误的

projects.get(soapFileName) != null

似乎应该有一个支持字段

public static HashMap<String,WsdlProject> projects = new HashMap<String,WsdlProject>();

public Object[] argumentsFromCallSoapui(CallT call, Vector<String> soapuiFiles, HashMap theDPLs,int messageSize)
{
    try {
        for (String soapFileName:soapuiFiles){
            System.out.println("Trying "+soapFileName);
            WsdlProject project ;
            if (projects.get(soapFileName) != null){
                project = projects.get(soapFileName);
            } else {
                project = new WsdlProject(soapFileName);
                projects.put(soapFileName,project);
            }
        }
    } ...
}

Answer 1

不。在 Java 中，静态变量仅初始化一次。

因此，该行只会被调用一次。

public static HashMap<String,WsdlProject> projects = new HashMap<String,WsdlProject> ();