python - 如何从我需要的文本中跳过或截断字符或符号。网页抓取与 BeautifulSoup

Question

我需要获取 div 标签之间的价格 (61,990)，但如何去掉货币符号？

与此处相同，我只需要获取评级 (4.7)，但之后我不需要任何内容​​，例如 img src。我怎么能忽视它呢？或者跳过它？

代码示例:

from bs4 import BeautifulSoup
import requests

price = []
ratings=[]
response = requests.get("https://www.flipkart.com/laptops/~buyback-guarantee-on-laptops-/pr?sid=6bo%2Cb5g&uniq")
soup = BeautifulSoup(response.text, 'html.parser')
for a in soup.findAll('a',href=True, attrs={'class':'_31qSD5'}): 
    price=a.find('div', attrs={'class':'_1vC4OE _2rQ-NK'})
    rating=a.find('div', attrs={'class':'hGSR34'})

Answer 1

这里。您只需使用 .text 方法并将其视为普通字符串即可。在这种情况下，保留除第一个字符之外的所有字符。

from bs4 import BeautifulSoup
import requests

price = []
ratings=[]
response = requests.get("https://www.flipkart.com/laptops/~buyback-guarantee-on-laptops-/pr?sid=6bo%2Cb5g&uniq")
soup = BeautifulSoup(response.text, 'html.parser')
for a in soup.findAll('a',href=True, attrs={'class':'_31qSD5'}):
    price=a.find('div', attrs={'class':'_1vC4OE _2rQ-NK'}).text[1:]
    rating=a.find('div', attrs={'class':'hGSR34'}).text
print(price)
print(rating)

Out[110]: '4.3'
Out[111]: '52,990'