python - 以完全错误的顺序打印代码

Question

```import random
from random import randint


pc = randint(1, 3)
playerinput = input("1 = Rock, 2 = Paper, 3 = Scissors")


def start():
    pc = randint(1, 3)

    if playerinput == 1:
        if pc == 2:
            print("You lose!")
        elif pc == 1:
            print("You draw!")
        else:
            print("You win!")


    elif playerinput == 2:
        if pc == 2:
            print("You draw!")
        elif pc == 3:
            print ("You lose!")
        else:
            print("You win!")

    else:
        if pc == 3:
            print("You draw!")
        elif pc == 2:
            print("You win!")
        else:
            print("You lose!")


again = input("Would you like to play again? Type 'YES' if so")
if again == "YES" or "yes" or "Yes" or "yEs" or "yeS" or "YEs" or "YeS":
    start()```

它会打印石头布或剪刀，然后就会显示“你想再玩一次吗”。如果你回答"is"，它就会打印出你是赢了、输了还是平局。怎么了？

Answer 1

您只调用玩家输入一次，因此一旦玩家做出决定，就会调用 start()只会生成一个新的随机 int。据我了解，你想将代码更改为这样的内容，每次都要求玩家输入start()叫做:(请注意，定义之前的 pc 也不需要，因为您在 start() 中重置了它)

import random
from random import randint

def start():
    pc = randint(1, 3)
    playerinput = input("1 = Rock, 2 = Paper, 3 = Scissors")

    if playerinput == 1:
        if pc == 2:
            print("You lose!")
        elif pc == 1:
            print("You draw!")
        else:
            print("You win!")


    elif playerinput == 2:
        if pc == 2:
            print("You draw!")
        elif pc == 3:
            print ("You lose!")
        else:
            print("You win!")

    else:
        if pc == 3:
            print("You draw!")
        elif pc == 2:
            print("You win!")
        else:
            print("You lose!")

start()

while True:
    again = input("Would you like to play again? Type 'YES' if so")
    if again == "YES" or "yes" or "Yes" or "yEs" or "yeS" or "YEs" or "YeS":
        start()
    else:
        break

编辑:正如另一个用户对您的问题的评论中所述，您应该将 if 更改为 if again.lower() = "yes" to be more clean. Also随机导入is not necessary if you call之后随机导入 randint`。