java - 如何创建 DRYer 构造函数

Question

有什么方法可以减少以下任何构造函数的重复吗？ IE。仅使用一个构造函数或没有多个“topping.add”调用？我的目标是制作一个可以有 1、2 或 3 种不同配料的披萨

private PizzaBase base;
List<PizzaTopping> toppings = new ArrayList<PizzaTopping>();

public Pizza(PizzaBase base, PizzaTopping topping) //Constructor for pizza with 1 topping
{
    setBase (base);
    toppings.add(topping);
}

public Pizza(PizzaBase base, PizzaTopping topping, PizzaTopping topping2) //Constructor for pizza with 2 toppings
{
    setBase (base);
    toppings.add(topping);
    toppings.add(topping2);
}

public Pizza(PizzaBase base, PizzaTopping topping, PizzaTopping topping2, PizzaTopping topping3) //Constructor for pizza with 3 toppings
{
    setBase (base);
    toppings.add(topping);
    toppings.add(topping2);
    toppings.add(topping3);

}

最初我正在考虑使用 for 循环将提供的配料添加到列表中，但我不确定如何迭代构造函数给出的值

Answer 1

使用可变参数，您可以使用任意数量的配料，并且不用担心构造函数内的情况，您可以将其视为列表

private PizzaBase base;
List<PizzaTopping> toppings = new ArrayList<PizzaTopping>();

public Pizza(PizzaBase base, PizzaTopping... toppings) //Constructor for pizza with 1 topping
{
    setBase (base);
    for(PizzaTopping topping : topings)
        toppings.add(topping);
}