python3 : how to print groupby. 最后()？

Question

$ cat n2.txt
apn,date
3704-156,11/04/2019
3704-156,11/22/2019
5515-004,10/23/2019
3732-231,10/07/2019
3732-231,11/15/2019

$ python3
Python 3.7.5 (default, Oct 25 2019, 10:52:18) 
[Clang 4.0.1 (tags/RELEASE_401/final)] :: Anaconda, Inc. on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> import pandas as pd 
>>> df = pd.read_csv("n2.txt")
>>> df
        apn        date
0  3704-156  11/04/2019
1  3704-156  11/22/2019
2  5515-004  10/23/2019
3  3732-231  10/07/2019
4  3732-231  11/15/2019
>>> g = df.groupby('apn')
>>> g.last()
                date
apn                 
3704-156  11/22/2019
3732-231  11/15/2019
5515-004  10/23/2019
>>> f = g.last()

>>> for r in f.itertuples(index=True, name='Pandas'):
...     print(getattr(r,'apn'), getattr(r,'date'))
... 
Traceback (most recent call last):
  File "<stdin>", line 2, in <module>
AttributeError: 'Pandas' object has no attribute 'apn'

>>> for r in f.itertuples(index=True, name='Pandas'):
...     print(getattr(r,"apn"), getattr(r,"date"))
... 
Traceback (most recent call last):
  File "<stdin>", line 2, in <module>
AttributeError: 'Pandas' object has no attribute 'apn'

将其打印到文件的正确方法是什么？

例如。

apn, date
3704-156,11/22/2019
3732-231,11/15/2019
5515-004,10/23/2019

Answer 1

df = pd.read_csv("n2.txt")
g = df.groupby('apn').last()
print(g.to_csv())

应该按照你的意愿工作。

如果您在控制台中输入 g.to_csv()，它会返回一个以 'apn,data,\r\n...' 开头的字符串。 print 函数遇到 '\r\n' 时会另起一行，最终按照您的意愿输出。