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php - 在ajax上传中实现JCrop

转载 作者:行者123 更新时间:2023-12-01 06:42:04 24 4
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我正在尝试使用 JQuery 开发图像裁剪。我使用ajax上传图片。图片成功完全上传后。我使用 jquery 将上传的图像加载到其容器中。

$("#image_upload").html("<img src='" + data.path + "' width=\"460\" id=\"cropbox\" alt=\"cropbox\" />");

但是图像选择不起作用。为什么会发生这种事?这是我的代码:

<style type="text/css">
#preview {
width: 150px;
height: 150px;
overflow: hidden;
}
</style>
<script type="text/javascript" src="<?php echo base_url()?>asset/jqupload/js/ajaxfileupload.js">
</script>
<script type="text/javascript" src="<?php echo base_url()?>asset/jcrop/jquery.Jcrop.pack.js">
</script>
<link rel="stylesheet" href="<?php echo base_url()?>asset/jcrop/jquery.Jcrop.css" type="text/css" />
<script type="text/javascript">
function ajaxFileUpload(){
$("#loading").ajaxStart(function(){

$(this).show();
}).ajaxComplete(function(){
$(this).hide();
});

$.ajaxFileUpload({
url: '<?php echo site_url()?>/upload/do_upload',
secureuri: false,
fileElementId: 'fileToUpload',
dataType: 'json',
success: function(data, status){
if (typeof(data.error) != 'undefined') {
if (data.error != '') {
$("#image_upload").html(data.error);
$("#image_upload").fadeIn("slow");
}
else {
$("#image_upload").html("<img src='" + data.path + "' width=\"460\" id=\"cropbox\" alt=\"cropbox\" />");
$("#image_upload").fadeIn("slow");
$("#orig_h").val(data.width);
$("#orig_w").val(data.height);
//alert("<a href='" + data.path + "' />");
}
}
},
error: function(data, status, e){
$("#image_upload").html(e);
$("#image_upload").fadeIn("slow");
}
})

return false;
}

$(document).ready(function(){
$(function(){
$('#cropbox').Jcrop({
aspectRatio: 1,
setSelect: [0, 0, $("#oring_w").val(), $("#oring_h").val()],
onSelect: updateCoords,
onChange: updateCoords
});
});

function updateCoords(c){
showPreview(c);
$("#x").val(c.x);
$("#y").val(c.y);
$("#w").val(c.w);
$("#h").val(c.h);
}

function showPreview(coords){
var rx = $("#oring_w").val() / coords.w;
var ry = $("#oring_h").val() / coords.h;

$("#preview img").css({
width: Math.round(rx * $("#oring_w").val()) + 'px',
height: Math.round(ry * $("#oring_h").val()) + 'px',
marginLeft: '-' + Math.round(rx * coords.x) + 'px',
marginTop: '-' + Math.round(ry * coords.y) + 'px'
});
}
});
</script>




<!-- begin main content -->
<div id="templatemo_content_area">
<h1 class="content_title">Label Info<hr/></h1>
<div id="templatemo_bi_full">
<h2>Label Setting</h2>
<div id="container">
</div>
<!--container-->
<br/>
<h2>Avatar</h2>
<div class="info">
</div>
<div id="avatar_container">
<form name="form" action="" method="POST" enctype="multipart/form-data">
<ul>
<li class="leftHalf ">
<label class="desc" for="lbl_type">
Change Your Avatar
</label>
<div>
<div id="avatar">
<img src="<?php echo $avatar?>" width="130" height="130" />
</div>
<div id="avatar_upload">
<input id="fileToUpload" name="fileToUpload" class="field field" value="" size="30" tabindex="5" type="file" /><input id="buttonUpload" name="buttonUpload" class="btTxt submit" type="submit" value="Upload" onclick="return ajaxFileUpload();"/><img id="loading" src="<?php echo base_url()?>asset/jqupload/images/loading.gif" style="display:none;">
</div>
</div>
</li>
</ul>
<ul id="crop_container">
<li class="leftHalf ">
<label class="desc" for="lbl_name">
Avatar for crop
</label>
<div id="image_upload">
<img src="<?php echo $avatar?>" width="450" height="130" id="cropbox" name="cropbox" />
</div>
</li>
<li class="rightHalf ">
<label class="desc" for="lbl_type">
Crop Display
</label>
<div id="preview">
<img src="<?php echo base_url() . 'files/' ?>" alt="thumb" />
</div>
</li>
<div class="info">
</div>
<li class="buttons ">
<input name="saveForm" class="btTxt submit" type="submit" value="Crop and Save" />
</li>
</ul>
<input type="text" id="x" name="x" />
<input type="text" id="y" name="y" />
<input type="text" id="w" name="w" />
<input type="text" id="h" name="h" />
<input type="text" id="oring_w" name="oring_w" />
<input type="text" id="oring_h" name="oring_h" />
</form>
</div>
<div class="cleaner">
</div>
</div>
<div class="cleaner">
</div>
</div>
<!-- end main content -->

请帮帮我......

最佳答案

它不起作用,因为你是通过 ajax 调用获取图像的。当您在 document.ready 上调用 jcrop 函数时,图像不存在。在 DOM 中添加图像后,您需要将 jcrop 代码放在 ajax 调用的成功函数中。应该是这样的(未测试):

    $.ajaxFileUpload({
url: '<?php echo site_url()?>/upload/do_upload',
secureuri: false,
fileElementId: 'fileToUpload',
dataType: 'json',
success: function(data, status){
if (typeof(data.error) != 'undefined') {
if (data.error != '') {
$("#image_upload").html(data.error);
$("#image_upload").fadeIn("slow");
}
else {
$("#image_upload").html("<img src='" + data.path + "' width=\"460\" id=\"cropbox\" alt=\"cropbox\" />");//it is important to add the jcrop code after this line
$("#image_upload").fadeIn("slow");
$("#orig_h").val(data.width);
$("#orig_w").val(data.height);
$('#cropbox').Jcrop({
aspectRatio: 1,
setSelect: [0, 0, $("#oring_w").val(), $("#oring_h").val()],
onSelect: updateCoords,
onChange: updateCoords
});

}
}
},
error: function(data, status, e){
$("#image_upload").html(e);
$("#image_upload").fadeIn("slow");
}
})

关于php - 在ajax上传中实现JCrop,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/2151672/

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