python - python 导入模块的问题

Question

我的模块有问题，无法在 python 中导入:它称为 instaloader。

当我想导入它时，它返回此错误消息:

import instaloader as i

Traceback (most recent call last):
  File "<console>", line 1, in <module>
  File "c:\users\oussama\anaconda3\lib\site-packages\instaloader\__init__.py", line 16, in <module>
    from .instaloader import Instaloader
  File "c:\users\oussama\anaconda3\lib\site-packages\instaloader\instaloader.py", line 2, in <module>
    import json
  File "C:\Users\Oussama\json.py", line 6, in <module>
    response=re.get("")
  File "c:\users\oussama\anaconda3\lib\site-packages\requests\api.py", line 75, in get
    return request('get', url, params=params, **kwargs)
  File "c:\users\oussama\anaconda3\lib\site-packages\requests\api.py", line 60, in request
    return session.request(method=method, url=url, **kwargs)
  File "c:\users\oussama\anaconda3\lib\site-packages\requests\sessions.py", line 519, in request
    prep = self.prepare_request(req)
  File "c:\users\oussama\anaconda3\lib\site-packages\requests\sessions.py", line 462, in prepare_request
    hooks=merge_hooks(request.hooks, self.hooks),
  File "c:\users\oussama\anaconda3\lib\site-packages\requests\models.py", line 313, in prepare
    self.prepare_url(url, params)
  File "c:\users\oussama\anaconda3\lib\site-packages\requests\models.py", line 387, in prepare_url
    raise MissingSchema(error)
requests.exceptions.MissingSchema: Invalid URL '': No schema supplied. Perhaps you meant http://?

如何解决这个问题？

Answer 1

您可以将 instaloader 导入为 import instaloader。 documentation for instaloader 表明您可以创建 instaloader 的实例并将其用于您的程序。

文档中的代码

import instaloader

L = instaloader.Instaloader()