python - __name__ 变量等于 "wsgi"而不是 "__main__"

Question

我有 wsgi 文件，其中有一行:

wsgi.py

if __name__ == "__main__":
    app.run()

但是今天我的服务器没有启动，当我打印 __name__ 时，发现它无缘无故地等于“wsgi”。我像“sudo systemctl restart myserver.service”一样启动我的服务器

myserver.ini

module = wsgi:app

master = true
processes = 3

socket = /var/www/myserver/myserver.sock
chmod-socket = 660
vacuum = true

die-on-term = true
logto = /var/www/myserver/server.log
enable-threads = true

myserver.service

Description=uWSGI instance to serve myserver
After=network.target

[Service]
User=savvasenok
Group=www-data
WorkingDirectory=/var/www/myserver
Environment="PATH=/home/savvasenok/MyServerEnv/bin"
ExecStart=/home/savvasenok/MyServerEnv/bin/uwsgi --ini /var/www/myserver/myserver.ini

[Install]
WantedBy=multi-user.target

Answer 1

正如 here 中所解释的那样:

If the source file is executed as the main program, the interpreter sets the __name__ variable to have a value “__main__”. If this file is being imported from another module, name will be set to the module’s name.

所以原因是您正在运行一个导入 wsgi 的 python 模块(或文件)。在您的情况下，我认为您将 wsgi 导入到 /home/savvasenok/MyServerEnv/bin/uwsgi 模块，您将其作为 ExecStart 并正在运行已执行。

您还可以查看this answer了解更多信息。