python - 如何从列表列表中获取整数

Question

我有这个列表:

lst =[[5,5,5,5],[5,0,1,5],[5,0,3,5],[5,2,3,5],[5,5,5,5]]

我需要某种函数来搜索一个特定的数字(例如 1)，其输出如下所示:

 >>> It's in a list with index 1
 >>> In list with index 1, it has index 2 

或者甚至更简单的东西，例如:

>>> 1
>>> 2

提前非常感谢您!

Answer 1

这是一个更简洁的版本，对我来说似乎更实用:

def find_int(l, target):
    sub_list = [x for x in range(len(l)) if target in l[x]][0]
    return sub_list, l[sub_list].index(target)


>>> lst = [[5,5,5,5],[5,0,1,5],[5,0,3,5],[5,2,3,5],[5,5,5,5]]
>>> print(find_int(lst,2))
(3, 1)

这是一个带有可爱文本的版本，它返回的结果与您指定的完全相同:

def find_int(l, target):
    for sub_list in range(len(l)):
        if target in l[sub_list]:
            print("It's in a list with index " + str(sub_list))
            print("In list with index " + str(sub_list) + ", it has index " + str(l[sub_list].index(target)))
            return

>>> lst = [[5,5,5,5],[5,0,1,5],[5,0,3,5],[5,2,3,5],[5,5,5,5]]
>>> find_int(lst,2)
It's in a list with index 3                                                                                                                    
In list with index 1, it has index 1