java - Java 代码中的 "misplaced construct(s)"靠近 catch

Question

我无法用 Java 编译以下代码，错误是:构造错误。怎么了？

public class ExceptionsTutorial {

    public static void main(String[] argv) throws Exception{

        try{
            System.out.println("A");

            try{
                System.out.println("B");
                throw new Exception("1");
            }
            catch{
                System.out.println("C");
                throw new Exception("2");
            }
            finally{
                System.out.println("D");
                throw new Exception("3");
            }

        }
        finally{
            System.out.println("F");
        }

    }
}

Answer 1

catch 必须声明它捕获的异常:

catch (Exception E) {
 System.out.println("C");
 throw new Exception("2");
}