java - 是否可以一次调用退回多件商品？

Question

以下元素是否可以在一次调用中返回多个项目(即两个 GRect)

    private GObject getColidingObject(){
    if(getElementAt(ball.getX(), ball.getY()) != null){
        return getElementAt(ball.getX(), ball.getY());
    }else if(getElementAt(ball.getX() + BALL_RADIUS *2, ball.getY()) != null){
        return getElementAt(ball.getX() + BALL_RADIUS *2, ball.getY());
    }else if(getElementAt(ball.getX(), ball.getY() + BALL_RADIUS *2) != null){
        return getElementAt(ball.getX(), ball.getY() + BALL_RADIUS *2);
    }else if(getElementAt(ball.getX() + BALL_RADIUS *2, ball.getY() + BALL_RADIUS *2) != null){
        return getElementAt(ball.getX() + BALL_RADIUS *2, ball.getY() + BALL_RADIUS *2);
    }else{
        return null;
    }
}

Answer 1

您只能返回一个值，但您可以将该值设为数组。例如:

private GObject[] getCollidingObjects() {
    GObject[] ret = new GObject[2];

    ret[0] = ...;
    ret[1] = ...;
    return ret;
}

顺便说一句，当您开始在同一方法中多次重复使用同一表达式时，为了清楚起见，您应该考虑引入局部变量。例如，考虑这个而不是您的原始代码:

private GObject getCollidingObject(){
    int x = ball.getX();
    int y = ball.getY();
    if (getElementAt(x, y) != null) {
        return getElementAt(x, y);
    }
    if (getElementAt(x + BALL_RADIUS * 2, y) != null) {
        return getElementAt(x + BALL_RADIUS * 2, y);
    }
    if (getElementAt(x, y + BALL_RADIUS * 2) != null) {
        return getElementAt(x, y + BALL_RADIUS * 2);
    }
    if (getElementAt(x + BALL_RADIUS * 2, y + BALL_RADIUS * 2) != null) {
        return getElementAt(x + BALL_RADIUS * 2, y + BALL_RADIUS * 2);
    }
    return null;
}

(您也可以对 x + BALL_RADIUS * 2 和 y + BALL_RADIUS * 2 执行相同的操作。)

您也可以考虑这样的事情:

private GObject getCollidingObject(){
    int x = ball.getX();
    int y = ball.getY();
    return getFirstNonNull(getElementAt(x, y),
        getElementAt(x + BALL_RADIUS * 2, y),
        getElementAt(x, y + BALL_RADIUS * 2),
        getElementAt(x + BALL_RADIUS * 2, y + BALL_RADIUS * 2));
}

private static getFirstNonNull(GObject... objects) {
    for (GObject x : objects) {
        if (x != null) {
            return x;
        }
    }
    return null;
}

(在 C# 中，有一种更好的方法可以使用空合并运算符来执行此操作，但没关系...)