python - newList = 列表 - 自身

Question

我有一个称为字符的对象列表，如下所示:

characters=[character(0,0,20,20,keys1),character(50,50,50,50,keys2),character(200,200,100,20,keys1)]

其中字符类定义为:

class character():
    def __init__(self,x,y,w,h,keys=keys1):
        self.x = x
        self.y = y
        self.w = w
        self.h = h
        self.keys = keys
        self.vel = 200 /math.sqrt(self.w*self.h)
        self.crashed=False
    # I need an list to use here in a function of my "character" class


 # my list must have all the elements in my initial list but self

我的意思是像

characters[0].myFunction() 必须具有 [characters[1],characters[2]] 列表 这是 characters =[character(50,50,50,50,keys2),character(200,200,100,20,keys1)]

Answer 1

您必须将完整列表作为参数传递给 .myFunction 才能知道从哪个列表中排除/过滤 self:

class character():

    def __init__(self,x,y,w,h,keys=keys1):
        self.x = x
        self.y = y
        self.w = w
        self.h = h
        self.keys = keys
        self.vel = 200 /math.sqrt(self.w*self.h)
        self.crashed = False

    def __repr__(self):
        return 'charcter({}, {}, {}, {}, {})'.format(
            self.x, self.y, self.w, self.h, self.keys)

    def myFunction(self, characters):
        return [e for e in characters if e != self] 

print(characters[0].myFunction(characters))

输出:

[charcter(50, 50, 50, 50, keys2), charcter(200, 200, 100, 20, keys1)]