python - 如何动态覆盖 Django Admin 中的 list_filter 字段？

Question

我在 list_filter 中有几个字段。我必须创建一个为 list_filter 中的每个值调用的通用 model.SimpleListFilter 。

我无法为每个 list_filter 创建单独的类。

最好的解决方案是这样的:

class MyModelAdmin(MyCustomFilter):
    list_filter = ('client_name', 'case_received_date')` 

为每个 list_filter 字段调用 MyCustomFilter 中的 lookups 和 queryset 方法。

# admin.py
class MyModelAdmin(admin.ModelAdmin):
    list_display = ('client_name','client_application_number')
    list_filter = ('client_name', 'case_received_date', MyCustomFilter)

class MyCustomFilter(admin.SimpleListFilter):    
    def lookups(self, request, model_admin):
        pass

    def queryset(self, request, queryset):
        # Apply the filter selected, if any
        pass

Answer 1

您可以使用函数生成无限数量的匿名类。以下是您的代码的更新:

class MyCustomFilter(admin.SimpleListFilter):
    def lookups(self, request, model_admin):
        pass

    def queryset(self, request, queryset):
        # Apply the filter selected, if any
        pass

def my_custom_filter_maker(field):
    class MyAnonymousCls(MyCustomFilter):
        title = field
        parameter_name = field

    return MyAnonymousCls

class MyModelAdmin(admin.ModelAdmin):
    list_display = ('client_name','client_application_number')
    list_filter = ('client_name', 'case_received_date', 
        my_custom_filter_maker('field_name'),  my_custom_filter_maker('another_field'))