python - 如何在 python mysql 中比较索引值与数据库值？

Question

我正在做的是将索引值与数据库的bar_code_no进行比较，如果bar_code_no通过索引值进行验证，那么我想打印经过验证的bar_code_no的整行，其中我有姓名，电子邮件，电话号码。我尝试过，但无法进行比较。

import mysql.connector as mysql
mydb1=mysql.connect(
        user = 'rajat',
        passwd = 'rajat',
        host = 'localhost',
        database = 'master_database'
        )
bal = []
validate =  ('1', 'Green', '12:34:56:78:91:22', '456456', '2')
val = validate[3]
bal.append(val)
print(bal)

new_list = []
mycursor3 = mydb1.cursor()
mycursor3.execute("SELECT bar_code_no FROM android_display_data")
df = mycursor3.fetchall()
print(df)

if bal in df:
    print('it exists')
else:
    print('it does not exists')

输出是这样的:-

['456456']
[('456456',)]
it does not exists

Answer 1

我得到了如何验证值的答案，但仍然遇到一个问题，即如何打印存在经过验证的 bar_code_no 的整行。

import mysql.connector as mysql
mydb1=mysql.connect(
        user = 'rajat',
        passwd = 'rajat',
        host = 'localhost',
        database = 'master_database'
        )
bal = []
validate =  ('1', 'Green', '12:34:56:78:91:22', '456456', '2')
val = validate[3]
bal.append(val)
print(bal)

new_list = []
mycursor3 = mydb1.cursor()
mycursor3.execute("SELECT bar_code_no FROM android_display_data")
df = mycursor3.fetchall()
df1 = df[0]
df2 = list(df1)
print(df2)


if bal == df2:
    print('its exists')
else:
    print('it does not exist')