python - 尝试获取可以根据输出进行检查的随机代码

Question

尝试使用 while 循环来要求用户输入打乱后的代码

• 如果为 true，则 login_success() 运行

• 否则 twofactor() 运行

但是，我无法将输入与打乱的代码相匹配，这与它是一个列表有关吗？我尝试过 .map 和 .join 但没有运气。

def twofactor():

    global RandomCode
    RandomCode = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
    flag = True

    while flag:
        random.shuffle(RandomCode)
        print(str(RandomCode[0:6]))
        entercode = str(input("Enter the code: "))
        if entercode != RandomCode:

            print("Incorrect code! ")
            print("A new code will generate below: ")
            twofactor()
        else:
            flag = FALSE
            print ("Success !")
            login_success()

Answer 1

import random
def login_success () :
    pass

def twofactor():

    global RandomCode
    RandomCode = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]

    flag = True

    while flag:
        random.shuffle(RandomCode)
        # --- Here's what you needed --- 
        RandomCodeString = ''.join (str (num) for num in RandomCode[0:6])
        print(RandomCodeString)
        entercode = str(input("Enter the code: "))
        if entercode != RandomCodeString:

            print("Incorrect code! ")
            print("A new code will generate below: ")
            twofactor()
        else:
            flag = False
            print ("Success !")
            login_success()

twofactor ()