python - 如何将 JSON 数组添加到 DRF 响应

Question

我有一个返回以下内容的 DRF ListAPIView:

count: 35652
next: "https://platform/events/?format=json&page=2"
previous: null
results: (50) [{…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}]
__proto__: Object

我需要向 View 或序列化器添加什么才能返回它？

count: 35652
next: "https://platform/events/?format=json&page=2"
previous: null
results: (50) [{…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}]
filter_data: ['filter element 1', 'filter element 2']
__proto__: Object

Answer 1

由于您使用 ListAPIView，因此您可以重写 list() 方法，请记住，此方法需要返回一个 Response 对象(也在源代码中 take a look代码)(受到 this SO answer 的启发)。

   def list(self, request, *args, **kwargs):
        response = super().list(request, args, kwargs)

        # you can add the data that you need in the response
        response.data['filter_data'] = ['filter element 1', 'filter element 2']

        return response

此外，don't forget .data 包含已经序列化的数据。