python - 在python中创建一个带有暂停函数的计时器

Question

有人帮助我制作了一个计时器，如果我按空格键，它就会重新启动。我想编辑此代码，以便当我按下返回/输入按钮时，它会暂停计时器，无论计时器位于何处(重新启动、在 0 处或在中间)。当然，我不希望它影响其余的代码。这是我的代码:

from turtle import Screen, Turtle, bgcolor
bgcolor('dodgerblue')
FONT = ("Arial", 60, "normal")

strings = input("Please enter the time: ").strip().split(' ')

time = [60 ** (len(strings) - index - 1) * int(unit) for index, unit in enumerate(strings)]

seconds = -1
ticking = False
def delSec(string):
    if len(string)==1:
        return "0"+string
    else:
        return string
def tick():
    global seconds, ticking

    turtle.clear()

    if seconds < 0:
        turtle.write("TIMER DONE", align='center', font=FONT)
        ticking = False
    else:
        turtle.write(delSec(str(seconds//3600))+":"+delSec(str((seconds%3600)//60))+":"+delSec(str((seconds%60)//1)), align='center', font=FONT)
        seconds -= 1
        screen.ontimer(tick, 1000)
key = "space"
def reset():
    global seconds, ticking, key

    screen.onkey(None, key)  # Disable event handler inside handler

    seconds = sum(time)

    if not ticking:
        ticking = True
        tick()

    screen.onkey(reset, key)  # Reenable event handler

screen = Screen()

turtle = Turtle()
turtle.hideturtle()
turtle.color('white')

reset()

screen.listen()
screen.mainloop()

如果有任何帮助，我将不胜感激，提前致谢!

<小时/>

编辑:我想要它，以便如果计时器暂停，我仍然可以重置它。

Answer 1

我使用键Return来运行更改paused的函数

def pause():
    global paused

    paused = not paused

并使用这个paused来控制tick()

def tick():
    global seconds, ticking

    if not paused:
        turtle.clear()

        if seconds < 0:
            turtle.write("TIMER DONE", align='center', font=FONT)
            ticking = False
            return
        else:
            turtle.write(delSec(str(seconds//3600))+":"+delSec(str((seconds%3600)//60))+":"+delSec(str((seconds%60)//1)), align='center', font=FONT)
            seconds -= 1

    screen.ontimer(tick, 1000)

tick() 必须运行 ontimer()，即使它暂停了

<小时/>

from turtle import Screen, Turtle, bgcolor

# --- functions ---

def delSec(string):
    if len(string) == 1:
        return "0" + string
    else:
        return string

def tick():
    global seconds, ticking

    if not paused:
        turtle.clear()

        if seconds < 0:
            turtle.write("TIMER DONE", align='center', font=FONT)
            ticking = False
            return
        else:
            turtle.write(delSec(str(seconds//3600))+":"+delSec(str((seconds%3600)//60))+":"+delSec(str((seconds%60)//1)), align='center', font=FONT)
            seconds -= 1

    screen.ontimer(tick, 1000)

def reset():
    global seconds, ticking, key,
    #global paused

    screen.onkey(None, key)  # Disable event handler inside handler
    screen.onkey(None, key_pause)  # Disable event handler inside handler

    seconds = sum(time)

    if not ticking:
        ticking = True
        tick()

    #paused = False

    screen.onkey(reset, key)  # Reenable event handler
    screen.onkey(pause, key_pause)  # Reenable event handler

def pause():
    global paused

    paused = not paused

# --- main ---

bgcolor('dodgerblue')
FONT = ("Arial", 60, "normal")

#strings = input("Please enter the time: ").strip().split(' ')
strings = '10'.strip().split(' ')

time = [60 ** (len(strings) - index - 1) * int(unit) for index, unit in enumerate(strings)]

seconds = -1
ticking = False
paused = False
key = "space"
key_pause = "Return"

screen = Screen()

turtle = Turtle()
turtle.hideturtle()
turtle.color('white')

reset()

screen.listen()
screen.mainloop()

<小时/>

要重置文本，即使它暂停，我也只暂停秒 -= 1 - 因此它会在每个循环中重绘时间 - 即使它暂停 - 所以重置可以更改值。

def tick():
    global seconds, ticking


    turtle.clear()

    if seconds < 0:
        turtle.write("TIMER DONE", align='center', font=FONT)
        ticking = False
        return
    else:
        turtle.write(delSec(str(seconds//3600))+":"+delSec(str((seconds%3600)//60))+":"+delSec(str((seconds%60)//1)), align='center', font=FONT)
        if not paused:
              seconds -= 1

    screen.ontimer(tick, 1000)