java - 如何高效处理Spring中的错误: Could not resolve view with name 'forward:/oauth/error'

Question

当 oauth2 client_id 无效时，我的其余 api 会创建此错误作为响应。

{"timestamp":"2016-10-06T05:26:31.367+0000","status":500,"error":"Internal Server Error","exception":"org.springframework.security.oauth2.provider.NoSuchClientException","message":"No client with requested id: backoffice","path":"/oauth/authorize"}

我的日志中有服务器端:

Looking up handler method for path /oauth/authorize
Did not find handler method for [/oauth/authorize]
Handling ClientRegistrationException error: No client with requested id: backoffice
Servlet.service() for servlet [dispatcherServlet] in context with path [] threw exception [Could not resolve view with name 'forward:/oauth/error' in servlet with name 'dispatcherServlet'] with root cause
javax.servlet.ServletException: Could not resolve view with name 'forward:/oauth/error' in servlet with name 'dispatcherServlet'
    at org.springframework.web.servlet.DispatcherServlet.render(DispatcherServlet.java:1237)
    ...
    at java.lang.Thread.run(Thread.java:745)

问题:防止服务器向他提供类异常并处理此错误的最佳方法是什么？

我尝试遵循 @ControllerAdvice 的建议，如 article 中所述。但代码从未通过断点:

@ControllerAdvice
public class GlobalExceptionHandler {
    private static final Logger logger = LoggerFactory.getLogger(GlobalExceptionHandler.class);
    @ExceptionHandler(NoSuchClientException.class)
    public String handleNoSuchClientException(HttpServletRequest request, Exception ex){
        logger.info("NoSuchClientException Occured:: URL="+request.getRequestURL());
        return "no_such_client_error";
    }
}

Answer 1

您需要将注释@ResponseBody添加到每个ControllerAdvice方法。