python - 通过从另一个列表中删除索引/值来返回新列表的最简单方法？ (需订购)

Question

全部，

o1 = ["a","b","c","d","e","f","g","h"]

index = [3,4]
value = ["c","d"]


[x for x in o1 if x not in value] 
[x for x in o1 if x not in [o1[y] for y in index]]

对于上述 lc 有更简单的解决方案吗？

谢谢

Answer 1

(x for x in o1 if x not in value)
(x for i, x in enumerate( o1 ) if i not in index )

请注意，使用生成器表达式将节省您遍历列表的次数，并且使用集合而不是列表作为索引和值会更有效。