python : How to handle multiple clients and a server

Question

我正在实现一个带有服务器和多个客户端的程序。所有客户端都将数据发送到服务器，服务器检查每个客户端的步骤。如果所有客户端的步骤都相同，则服务器会向所有客户端发送新数据以执行下一步。并且它一次又一次地继续这个过程。

但是，当我运行我的程序时，它无法相互通信。这是我的代码。你能给我一些提示吗？

客户端和服务器

#client
from socket import *
from sys import *
import time
import stat, os
import glob

# set the socket parameters
host = "localhost"
port = 21567
buf = 1024
data = ''
addr = (host, port)

UDPSock = socket(AF_INET, SOCK_DGRAM)
UDPSock.settimeout(100)

def_msg = "=== TEST ==="

#FILE = open("test.jpg", "w+")
FILE = open("data.txt","w+")

while (1):
  #data, addr = UDPSock.recvfrom(buf)
  print "Sending"
  UDPSock.sendto(def_msg, addr)
  #time.sleep(3)
  data, addr = UDPSock.recvfrom(buf)

  if data == 'done':
   FILE.close()
   break
  FILE.write(data)

  print "Receiving"
  #time.sleep(3)

UDPSock.close()

# server program for nvt

from socket import *
import os, sys, time, glob
#import pygame
import stat

host = 'localhost'
port = 21567
buf = 1024
addr = (host, port)

print 'test server'

UDPSock = socket(AF_INET, SOCK_DGRAM)
UDPSock.bind(addr)

msg = "send txt file to all clients"

#FILE = open("cam.jpg", "r+")
FILE = open("dna.dat","r+")
sending_data = FILE.read()
FILE.close()

tmp_data = sending_data

while (1):
  #UDPSock.listen(1)
  #UDPSock.sendto(msg, addr)
  #FILE = open("gen1000.dat","r+")
  #sending_data = FILE.read()
  #FILE.close()


  #print 'client is at', addr
  data, addr = UDPSock.recvfrom(buf)
  #time.sleep(3)
  print data
  #msg = 'hello'

  # 
  tmp, sending_data = sending_data[:buf-6], sending_data[buf-6:]

  if len(tmp) < 1:
    msg = 'done'
    UDPSock.sendto(msg, addr)
    print "finished"
    sending_data = tmp_data

  UDPSock.sendto(tmp, addr)
  print "sending"
  #time.sleep(3)
UDPSock.close()

Answer 1

服务器必须执行socket()、bind()、listen()、accept()序列code> (可能重复 accept() 来服务多个客户端)，而客户端只需要序列 socket(), connect().

我首先看到的是你丢失的listen()。监听与套接字建立的连接。

更多信息请参见:link text